可以将bitset< 8>到c ++中的char？ [英] Is it possible to convert bitset<8> to char in c++?

问题描述

我有bitset< 8> v8，它的值是类似11001101，我怎么转换成char？我需要一封信。喜欢字母f= 01100110。

I have bitset<8> v8 and its value is something like "11001101", how can I convert it to char? I need a single letter. Like letter "f"=01100110.

感谢帮助。我需要这个来说明位的随机错误。例如没有错误f，有错误的东西像♥，等等与文件中的所有文本。在文本中，您可以清楚地看到此类错误。

P.S. Thanks for help. I needed this to illustrate random errors in bits. For example without error f, and with error something like ♥, and so on with all text in file. In text you can see such errors clearly.

推荐答案

unsigned long i = mybits.to_ulong(); 
unsigned char c = static_cast<unsigned char>( i ); // simplest -- no checks for 8 bit bitsets

请注意，位字段可能包含无法使用简单 char （它是实现定义是否已签名）表示的值 - 因此您应该总是先检查

Something along the lines of the above should work. Note that the bit field may contain a value that cannot be represented using a plain char (it is implementation defined whether it is signed or not) -- so you should always check before casting.

char c;
if (i <= CHAR_MAX) 
c = static_cast<char>( i );

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