使用boost :: filesystem遍历目录，而不抛出异常 [英] Traversing a directory with boost::filesystem without throwing exceptions

问题描述

我有一个目录路径，我想遍历所有的子目录，收集文件的路径。

I have a path to the directory, and I want to traverse through all of its sub-directories, collecting files' pathes by the way.

namespace fs = boost::filesystem;

std::vector<fs::path> traverse_if_directory(fs::path& f) {
    std::vector<fs::path> result;
    if (fs::is_directory(f)) {      
        for (fs::recursive_directory_iterator it(f), eit; it != eit; ++it) {
            if (!fs::is_directory(it->path())) {
                result.push_back(it->path());
            }       
        }
    }
    else {
        result.push_back(f);
    }

    return result;
}

不幸的是，在遍历的过程中，没有权利看看，而上面的代码抛出。但显然，在这种情况下，它不是一个例外，我应该继续，跳过这个锁定的目录。

Unfortunately, in the middle of the traversing, I stumble upon a directory which I have no rights to look at, and the code above throws. But obviously, in this scenario it's not an exception, I should just go on, skipping this locked directory.

但是我该怎么做呢？

推荐答案

哈，想出来，有一种方法：

Ha, figured it out, there is a way:

std::vector<fs::path> traverse_if_directory(fs::path& f) {
    std::vector<fs::path> result;
    boost::system::error_code ec;

    if (fs::is_directory(f)) {      
        for (
             fs::recursive_directory_iterator it(f, ec), eit;
             it != eit;
             it.increment(ec)
            ) {
            if (ec) {
                it.pop();
                continue;
            }
            if (!fs::is_directory(it->path())) {
                result.push_back(it->path());
            }
        }
    }
    else {
        result.push_back(f);
    }

    return result;
}

有一个非throwing重载，接受一个< c $ c> boost :: system :: error_code ，所以我可以检查每个增量之后如果有任何错误。

There is a non-throwing overload which accepts an output parameter of type boost::system::error_code, so I can just check after each increment if there were any error.

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