正则表达式源代码注释 [英] Regex to source code comments

问题描述

是否有正则表达式匹配任何行注释，但避免字符串中的注释？
我需要 // （包括 // ）之后的所有内容

Is there a regular expression to match any line comment, but avoiding the comments inside strings? I need all content in a line after // (with the // included)

例如：

//Comment (match!)
bla bla bla bla //Comment (match!)
this string "foo // foo" (don't match because it's inside "")

推荐答案

这里是另一个解决方案，应该捕获每一个单行注释（看到它工作在 regex101 ）：

Here's another solution that should catch every single-line comment (see it work on regex101):

（\ / \ /。 *）|（？：\\|。）*？

所有注释将在第一个匹配

All the comments will be captured in the first match group.

它可以在任何正则表达式中使用惰性量词，这几乎是所有的。我使用的技术是匹配引用的字符串，删除从可用的文本匹配我们想要的：评论。这个技术在RexEgg.com上详细解释为 The Greatest Regex Trick Ever 。

It will work in any regex flavor that has lazy quantifiers, which is almost all of them. The technique I used is to match quoted strings specifically so they get "removed" from the text available to match what we want: comments. This technique is explained in detail on RexEgg.com as The Greatest Regex Trick Ever.

细分：

（\ / \ /.*)匹配注释并捕获组

：\\|。）*？匹配引用字符串，避免

"(?:\\"|.)*?" matches quoted strings, avoiding any escaped quotes inside

• 内部非捕获组（?: \\|。）匹配转义的引号或下一个字符，成功地跨越转义引号，而不是它们匹配作为真实报价


• 整个替换具有 *？惰性量词，所以它命中下一个而不是转到另一个带引号的字符串。

• The inside non-capturing group (?:\\"|.) matches an escaped quote OR the next character, successfully passing right over the escaped quotes rather than having them match as a "real" quote
• The whole alternation has the *? lazy quantifier so it hits the next "real" quote, rather than proceeding to another quoted string.

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