从输入读取字符串直到EOF [英] read strings from input till EOF

问题描述

我已经阅读了SO的许多帖子，但仍然无法解决这个问题。

我必须阅读：

文字

pattern1

pattern2

，有许多文本和模式。

代码：

  string t，p1，p2; 
 while（getline（cin，t））
 {
 cin>> p1; 
 cin>> p2; 
 
 cout<<text is =<< t<<\\\
p1 is =< p2 is =< ; p2 } 
  

输入文件：

锤子

ham

mer

gogoa

go < br>
z

gogoa

g

o

输出：：：

p2 is = mer

text is =

p1 is = gogoa

p2 is = go

text is =

p1 is = z

p2 is = gogoa

text is =

p1 is = g

p2 is = o

解决方案

如果您在 cin>>

$ b

  #include< iostream> 
 #include< limits> 
 using namespace std; 
 
 int main（）{
 string t，p1，p2; 
 while（getline（cin，t））
 {
 cin>> p1; 
 cin>> p2; 
 
 cout<<text is =<< t<<\\\
p1 is =< p2 is =< ; p2 < 
 cin.ignore（std :: numeric_limits< std :: streamsize> :: max（），'\\\
'）; // Dump everything until newline 
} 
 return 0; 
} 
  

http://ideone.com/b7Xj6o

更多此处：http://stackoverflow.com/a/10553849/1938163

I have gone through many posts on SO , but still i am not able to resolve the issue .
I have to read :

text
pattern1
pattern2

from standard input , there are many text and patterns .
Code :

string t,p1,p2;
while(getline(cin, t))
{
    cin>>p1;
    cin>>p2;

    cout<<"text is = "<<t<<"\np1 is = "<<p1<<"\np2 is = "<<p2<<endl;
}  

Input file :

hammer
ham
mer
gogoa
go
z
gogoa
g
o

Output :

text is = hammer
p1 is = ham
p2 is = mer
text is =
p1 is = gogoa
p2 is = go
text is =
p1 is = z
p2 is = gogoa
text is =
p1 is = g
p2 is = o

解决方案

If you're using getline after cin >> something, you need to flush the newline out of the buffer in between.

#include <iostream>
#include <limits>
using namespace std;

int main() {
    string t,p1,p2;
    while(getline(cin, t))
    {
        cin>>p1;
        cin>>p2;

        cout<<"text is = "<<t<<"\np1 is = "<<p1<<"\np2 is = "<<p2<<endl;

        cin.ignore (std::numeric_limits<std::streamsize>::max(), '\n'); // Dump everything until newline
    }
    return 0;
}

http://ideone.com/b7Xj6o

More here: http://stackoverflow.com/a/10553849/1938163

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