将long转换为char * const [英] Convert long to char* const

问题描述

在C ++中将 long 转换为 char * const 的正确方法是什么？

编辑：

  long l = pthread_self 
 ThirdPartyFunction（Thread_Id _+ l）; //需要这样做
 
 
 ThirdPartyFunction（char * const identifierString）
 {} 
  

解决方案

编辑：
在C ++中将整数转换为字符串的正确方法是使用stringstream。例如：

  #include< sstream> 
 
 std :: ostringstream oss; 
 oss<< Thread_Id_<< l; 
 ThirdPartyFunction（oss.str（）。c_str（））; 
  

现在，这可能不是最快的方式

>

取决于convert的意思。

要转换 long 的内容到指针：

  char * const p = reinterpret_cast< char * const>（your_long）; 
  

要查看 long 数组 char s：

  char * const p = reinterpret_cast< char * const>（& your_long）; 
  

要将 long 转换为 string ：

  std :: ostringstream oss; 
 oss<<你的_ 
 std :: string str = oss.str（）; 
 // optionaly：
 char * const p = str.c_str（）; 
  

What is the right way to convert long to char* const in C++?

EDIT:

long l = pthread_self();
ThirdPartyFunction("Thread_Id_"+l); //Need to do this


ThirdPartyFunction(char* const identifierString)
{}

解决方案

EDIT: The "proper" way to convert an integer to a string, in C++, is to use a stringstream. For instance:

#include <sstream>

std::ostringstream oss;
oss << "Thread_Id_" << l;
ThirdPartyFunction(oss.str().c_str());

Now, that probably won't be the "fastest" way (streams have some overhead), but it's simple, readable, and more importantly, safe.

---

OLD ANSWER BELOW

Depends on what you mean by "convert".

To convert the long's contents to a pointer:

char * const p = reinterpret_cast<char * const>(your_long);

To "see" the long as an array of chars:

char * const p = reinterpret_cast<char * const>(&your_long);

To convert the long to a string:

std::ostringstream oss;
oss << your_long;
std::string str = oss.str();
// optionaly:
char * const p = str.c_str();

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