C ++ is“const void”作为返回值更多的Const-Correct比“void”？ [英] C++ Is "const void" As Return Value More Const-Correct Than "void"?

问题描述

当我谈到编程时，我已经成为一个const正确的狂热者。我有const无处不在（当然正确）。现在我甚至开始const我的void返回类型。

你不能创建一个void对象，因此你不能给一个void对象分配一个值，即使它是const或者不是，这意味着const成为多余的。

我希望这个isn'

 对于Stack Overflow， const void Foo（void）; 
  

vs

  void Foo（void）; 
  

有什么区别吗？

解决方案

不， const void 是完全没有意义的。我很惊讶你的编译器不给你警告，实际上。例如，Clang告诉我：

  example.cpp：1：1：warning：'const'没有效果
 [-Wignored-qualifiers] 
 const void Foo（void）; 
 ^ ~~~~~ 
 1生成警告。 
  

I have become somewhat of a const-correctness fanatic when it comes to programming. I've got const's everywhere (where correct of course). Now I've even started const'ing my void return types.

You can't create a void object and therefore you can't assign a value to a void object even if it's const or not, which means the "const" becomes redundant.

So am I const'ing my void return types for nothing?

I hope this isn't too philosophical for Stack Overflow.

TL;DR:

const void Foo( void );

vs

void Foo( void );

Is there any difference?

解决方案

No, const void is completely meaningless. I'm surprised your compiler doesn't give you a warning, actually. Clang, for instance, told me:

example.cpp:1:1: warning: 'const' type qualifier on return type has no effect
      [-Wignored-qualifiers]
const void Foo( void );
^~~~~~
1 warning generated.

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