按返回类型重载模板 [英] Overloading template by Return Type

问题描述

Mooing Duck 发表了评论这里一个函数不能返回多个类型。但是，你可以专门化或委托重载，罚款。

Mooing Duck makes a comment here that "One function can't return multiple types. However, you can specialize or delegate to overloads, which works fine."

我开始思考这个问题，我想知道这个法律代码是什么：

I started thinking about that, and I'm trying to figure out, how is this legal code:

template <typename T>
T initialize(){ return T(13); }

当调用时：

auto foo = initialize<int>();
auto bar = initialize<float>();

不是那个翻译成同名的两个函数只被返回类型重载？ p>

Doesn't that translate to 2 functions of the same name overloaded by return-type only?

推荐答案

这不是一个重载，它是一个专业化。它们是不同的机制（事实上混合两者可能导致混乱，因为超载在专业化之前被解决 - 参见Sutter's Mill文章例如： http://www.gotw.ca/publications/mill17.htm ）。

It's not an overload, it's a specialization. They are different mechanisms (in fact mixing the two can lead to confusion, because overloads are resolved before specializations are considered -- see this Sutter's Mill article for example: http://www.gotw.ca/publications/mill17.htm).

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