初始化作为类成员的struct [英] Initialising a struct which is member of class

问题描述

这是我的代码：

  ... 
 #includemyheader.h
 
 myClass :: myStruct Foo; 
 
 Foo.one = 1; 
 Foo.two = 2; 
 
 myClass myclass（Foo）; 
 ... 
  

这是我的头文件类：

  class myClass：baseClass {
 public：
 struct myStruct {
 myStruct（）：
 one （0），
 two（0）{} 
 int one; 
 int two; 
}; $ b $b myClass（const myStruct& mystruct）; 
}; 
  

但这是无法编译，我想我正确访问元素一和二...
我得到这个错误：

：预期的构造函数，析构函数或类型转换。

我错了什么？

解决方案

  Foo.one = 1; 
  

这是一个语句，它需要进入一个函数或方法定义。语句不能单独出现在源文件的顶层。

尝试将此代码放在函数内部，例如入口点 main （）：

  int main（）{
 myClass :: myStruct Foo; 
 
 Foo.one = 1; 
 Foo.two = 2; 
 
 myClass myclass（Foo）; 
 
 return 0; 
} 
  

Here is my code:

...
#include "myheader.h"

myClass::myStruct Foo;

Foo.one = 1;
Foo.two = 2;

myClass myclass(Foo);
...

This is my class from the header file:

class myClass : baseClass{
public:
struct myStruct {
myStruct():
one(0),
two(0){}
int one;
int two;
};
myClass(const myStruct &mystruct);
};

But this is failing to compile, I think I am accessing the elements one and two in the proper way... I get this error:

: expected constructor, destructor, or type conversion before '.' token .

Where a m I going wrong?

解决方案

Foo.one = 1;

This is a statement, and it needs to go inside of a function or method definition. Statements cannot appear by themselves at the top level of a source file.

Try putting this code inside of a function, for example the entry point main():

int main() {
    myClass::myStruct Foo;

    Foo.one = 1;
    Foo.two = 2;

    myClass myclass(Foo);

    return 0;
}

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