的WebMethod返回JSON,但OBJ在我的$就响应()回调仅仅是一个字符串 [英] WebMethod returning JSON but the response obj in my $.ajax() callback is only a string
问题描述
下面是我自制的序列化类:
公共类JsonBuilder
{
私人StringBuilder的JSON;
公共JsonBuilder()
{
JSON =新的StringBuilder();
}
公共JsonBuilder AddObjectType(字符串的className)
{
json.Append(\+的className +\:{);
回到这一点;
}
公共JsonBuilder添加(字符串键,字符串VAL)
{
json.AppendFormat(\{0} \:\{1} \,键,VAL);
回到这一点;
}
公共JsonBuilder添加(字符串键,诠释VAL)
{
json.AppendFormat(\{0} \:{1},键,val)的;
回到这一点;
}
公共字符串序列化()
{
返回json.ToString()TrimEnd(新的char [] {','})+}。
}
}
下面是Web方法
[WebMethod的]
公共静态字符串GetPersonInfo(字符串pFirstName,串pLastName)
{
VAR JSON =新JsonBuilder()AddObjectType(人)。
json.Add(名字,的伪+ pFirstName)。新增(姓氏,Tally-+ pLastName);
。json.Add(地址,5035麦克雷路SE)添加(城市,萨利姆);
。json.Add(国家,俄勒冈州)添加(ZIP code,97317)添加(时代,99);
返回json.Serialize();
}
Ajax调用客户端
$。阿贾克斯(
{
键入:POST,
网址:Default.aspx的/ GetPersonInfo
数据:JSON.stringify(名称),
的contentType:应用/ JSON的;字符集= UFT-8,
数据类型:JSON,
成功:函数(RSP){SetPerson(RSP); },
错误:函数(RSP)
{
警报(RSP);
}
});
最后,我的回调方法
函数SetPerson(RSP)
{
$('#FNAME)VAL(rsp.d.FirstName)。
$('#L-NAME)VAL(rsp.d.LastName)。
$('#地址)VAL(rsp.d.Address)。
$('#城市)VAL(rsp.d.City)。
$('#国家)VAL(rsp.d.State)。
$('#拉链)VAL(rsp.d.Zip code)。
SetPerson(rsp.d.Age);
}
rsp.d是包含所有属性...属性本身是不确定的字符串。我知道我失去了一些东西简单的在这里。
从服务器返回的字符串
人:{姓:Psuedomatt,姓氏:理货 - 考克斯,地址:5035麦克雷路SE,城市: 萨利姆,国家:俄勒冈州,邮编code:97317,时代:99}
您不能手动序列化的返回值; ASP.NET会为你做它。尝试是这样的:
[WebMethod的]
公共静态人GetPersonInfo(字符串pFirstName,串pLastName)
{
//假设你有一个服务器端的Person类。
者P =新的Person();
p.FirstName =伪+ pFirstName;
p.LastName =Tally-+ pLastName;
p.Address =5035麦克雷路SE;
p.City =萨利姆;
p.State =俄勒冈州;
p.Zip code =97317;
// ASP.NET会自动JSON序列化这一点,如果你把它
//正确的客户端的形式(你似乎做的)。
返回磷;
}
如果你需要返回的东西更有活力,喜欢你的例子似乎做的事情,你可以使用匿名类型:
[WebMethod的]
公共静态对象GetPersonInfo(字符串pFirstName,串pLastName)
{
// ASP.NET会自动JSON序列化这一点。
返回新{
名字=伪+ pFirstName,
姓氏=Tally-+ pLastName,
地址=5035麦克雷路SE,
市=萨利姆
国家=俄勒冈州,
邮编code =97317
}
}
Here is my home-made Serializing class:
public class JsonBuilder
{
private StringBuilder json;
public JsonBuilder()
{
json = new StringBuilder();
}
public JsonBuilder AddObjectType(string className)
{
json.Append("\"" + className + "\": {");
return this;
}
public JsonBuilder Add(string key, string val)
{
json.AppendFormat("\"{0}\":\"{1}\",", key, val);
return this;
}
public JsonBuilder Add(string key, int val)
{
json.AppendFormat("\"{0}\":{1},", key, val);
return this;
}
public string Serialize()
{
return json.ToString().TrimEnd(new char[] { ',' }) + "}";
}
}
Here is the Web Method
[WebMethod]
public static string GetPersonInfo(string pFirstName, string pLastName)
{
var json = new JsonBuilder().AddObjectType("Person");
json.Add("FirstName", "Psuedo" + pFirstName).Add("LastName", "Tally-" + pLastName);
json.Add("Address", "5035 Macleay Rd SE").Add("City", "Salem");
json.Add("State", "Oregon").Add("ZipCode", "97317").Add("Age", 99);
return json.Serialize();
}
The Ajax call client-side
$.ajax(
{
type: "POST",
url: "Default.aspx/GetPersonInfo",
data: JSON.stringify(name),
contentType: "application/json; charset=uft-8",
dataType: "json",
success: function (rsp) { SetPerson(rsp); },
error: function (rsp)
{
alert(rsp);
}
});
And finally, my callback method
function SetPerson(rsp)
{
$('#fName').val(rsp.d.FirstName);
$('#lName').val(rsp.d.LastName);
$('#address').val(rsp.d.Address);
$('#city').val(rsp.d.City);
$('#state').val(rsp.d.State);
$('#zip').val(rsp.d.ZipCode);
SetPerson(rsp.d.Age);
}
rsp.d is a string that contains all the properties ... the properties themselves are undefined. I know I am missing something simple here.
Returned string from server
"Person": {"FirstName":"Psuedomatt","LastName":"Tally-cox","Address":"5035 Macleay Rd SE","City":"Salem","State":"Oregon","ZipCode":"97317","Age":99}
You shouldn't manually serialize the return value; ASP.NET will do it for you. Try something like this:
[WebMethod]
public static Person GetPersonInfo(string pFirstName, string pLastName)
{
// Assuming you have a server-side Person class.
Person p = new Person();
p.FirstName = "Pseudo" + pFirstName;
p.LastName = "Tally-" + pLastName;
p.Address = "5035 Macleay Rd SE";
p.City = "Salem";
p.State = "Oregon";
p.ZipCode = "97317";
// ASP.NET will automatically JSON serialize this, if you call it with
// the correct client-side form (which you appear to be doing).
return p;
}
If you need to return something more dynamic, like your example seems to be doing, you can use an anonymous type:
[WebMethod]
public static object GetPersonInfo(string pFirstName, string pLastName)
{
// ASP.NET will automatically JSON serialize this as well.
return new {
FirstName = "Pseudo" + pFirstName,
LastName = "Tally-" + pLastName,
Address = "5035 Macleay Rd SE",
City = "Salem",
State = "Oregon",
ZipCode = "97317"
}
}
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