将双精度列表规范化为范围-1到1或0-255 [英] normalizing a list of doubles to range -1 to 1 or 0 - 255

问题描述

我有一个在 -1.396655 到 1.74707 之间的范围内的双精度的列表甚至可以更高下，任何一种方式我会知道 Min 和 Max 值是在规范化之前。我的问题是如何规范这些值之间的 -1 到 1 或更好的将它们从双值转换char值 0 至 255

  double range =（double）（max  -  min）; 
 value = 255 *（value  -  min）/ range 
  

解决方案>

最简单的事情是首先通过从每个数字中减去Min来移动所有的值，使得min为0。然后乘以255 /（Max-Min），使得移位的Max将被映射到255，并且一切将会线性缩放。所以我相信你的方程如下：

newval =（unsigned char）（oldval - Min）*（255 / Min）））

在转换为char之前，您可能要更仔细一些。

I have a list of doubles in the range of anywhere between -1.396655 to 1.74707 could even be higher or lower, either way I would know what the Min and Max value is before normalizing. My question is How can I normalize these values between -1 to 1 or even better yet convert them from double values to char values of 0 to 255

Any help would be appreciated.

double range = (double)(max - min);
value = 255 * (value - min)/range

解决方案

The easiest thing is to first shift all the values so that min is 0, by subtracting Min from each number. Then multiply by 255/(Max-Min), so that the shifted Max will get mapped to 255, and everything else will scale linearly. So I believe your equation would look like this:

newval = (unsigned char) ((oldval - Min)*(255/(Max-Min)))

You may want to round a bit more carefully before casting to char.

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