不能使用“不是”，“或”，或“加”作为标识符？ [英] Can't use "not", "or", or "plus" as identifier?

问题描述

我试着编译这个：

enum class conditional_operator { plus, or, not };

但是显然GCC（4.6）认为这些都是特殊的，而我找不到一个标准它们（不是C ++ 0x n3290或C99 n2794）。我正在编译 g ++ -pedantic -std = c ++ 0x 。这是一个编译器方便吗？如何关闭它？不应 -std = c ++ 0x 关闭此功能？

But apparently GCC (4.6) thinks these are special, while I can't find a standard that says they are (neither C++0x n3290 or C99 n2794). I'm compiling with g++ -pedantic -std=c++0x. Is this a compiler convenience? How do I turn it off? Shouldn't -std=c++0x turn this "feature" off?

PS：Hmmm，显然，MarkDown代码格式化也认为这样...

PS: Hmmm, apparently, MarkDown code formatting thinks so too...

推荐答案

看看2.5。它们是 || 和！的替代标记。

Look at 2.5. They are alternative tokens for || and !.

有一堆其他替代令牌BTW。

There is a bunch of other alternative tokens BTW.

编辑：它们的包含的原理是一样的trigraphs：允许使用非ASCII字符集。委员会试图摆脱它们（至少是三字母，我不记得替代令牌），并遇到了人们（大多数是IBM大型机用户）使用它们的反对。

The rationale for their inclusion is the same as the one of trigraphs: allow the use of non ASCII character sets. The committee has tried to get rid of them (at least of trigraphs, I don't remember for alternative tokens), and has met opposition of people (mostly IBM mainframe users) which are using them.

编辑完整性：as other have make the remarks，plus不在该类中，除非你是 using namespace std 。

Edit for completeness: as other have make the remarks, plus isn't in that class and should not be a problem unless you are using namespace std.

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