C ++编译器错误涉及私人继承 [英] C++ compiler error involving private inheritance

问题描述

有人可以向我解释以下编译器错误：

Could someone please explain the following compiler error to me:

struct B
{
};

template <typename T>
struct A : private T
{
};

struct C : public A<B>            
{                                                                             
    C(A<B>);   // ERROR HERE
};

指示行处的错误是：

test.cpp:2:1: error: 'struct B B::B' is inaccessible
test.cpp:12:7: error: within this context

推荐答案

解决方案

尝试 A< :: B> 或 A< struct B> 。

c $ c> C ，对$ B 的非限定引用将选择所谓的 inject-class-name 它通过基类 A 引入。由于 A 从 B 私下继承，因此 injected-class-name 也是私人的，因此无法访问 C 。

Inside of C, unqualified references to B will pick up the so-called injected-class-name, it is brought in through the base class A. Since A inherits privately from B, the injected-class-name follows suit and will also be private, hence be inaccessible to C.

另一天，另一种语言quirk ...

Another day, another language quirk...

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