功能专用模板问题 [英] Function specialized template problem
问题描述
我是模板的新用户。我尝试定义专门的模板功能模板,但我的编译器返回错误。它是简单的最大功能,只写实践模板;这里是代码:
template< typename TYP1,typename TYP2> TYP1最大值(TYP1& param1,TYP2& param2)
{
return(param1> param2?param1:param2);
}
和专用功能:
模板<> std :: string maximum< std :: string,std :: string>(std :: string prm1,std :: string prm2)
{
std :: cout< 内部专业功能
return(prm1.length()> prm2.length()?prm1:prm2);
}
如果我试图为std :: string或任何其他类型,包括我自己定义的类 - 错误总是相同:
错误C2912:显式专门化;'std :: string maximum(std :: string,std :: string)'不是函数模板的特殊化...
IntelliSense建议:没有函数模板实例
$请提前感谢
你忘了字符串前面的&
它期望参考类型,你的专业化是使用值类型。
模板< std :: string maximum< std :: string,std :: string>(std :: string& prm1,std :: string& prm2)
I am new to templates. I try to define specialized template for function template, but my compiler returns error. It is simple max function, written just to practice templates; here's the code:
template <typename TYP1, typename TYP2> TYP1 maximum(TYP1& param1, TYP2& param2)
{
return (param1 > param2 ? param1 : param2);
}
and specialized function:
template<> std::string maximum<std::string, std::string>(std::string prm1, std::string prm2)
{
std::cout << "Inside specialized functiion\n";
return (prm1.length() > prm2.length() ? prm1 : prm2);
}
It doesn't matter if I try to write specialization for std::string or any other type, including my own defined classes - the error is always the same:
"error C2912: explicit specialization; 'std::string maximum(std::string,std::string)' is not a specialization of a function template ... "
IntelliSense suggest: "no instance of function template"
What should I change to make this compile and work properly?
Thanks in advance
You're forgetting the &
in front of the strings. It expects reference types, your "specialization" is using value types.
template<> std::string maximum<std::string, std::string>(std::string &prm1, std::string &prm2)
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