force const存储由值返回的值 [英] force const storing of returned by value value

问题描述

这是我想要完成的：

struct test{};

const test returnconst(){
    return test();
}

test returnnonconst(){
    return test();
}

int main(){
          test t1=returnnonconst();
    const test t2=returnnonconst();
          test t3=returnconst();  //I want this to be a compile error
    const test t4=returnconst();
}

编译器接受所有四个return *调用。我理解，在第三次调用一个对象的副本被构造，但我想要而不是强制调用 returnconst 将值存储为 const 。是否有解决方法？

The compiler accepts all of the four return* calls. I understand that in the third call a copy of the object is constructed, but I want instead to force the caller of returnconst to store the value as const. Are there workaround to this?

推荐答案

您按值返回。您正在创建副本 const 。所以你基本上是说你不想复制 const ：

You're returning by value. You're creating a copy of a const. So you're basically saying you don't want to be able to make copies of const:

前面的代码不工作，你会得到吨的其他错误。这是不可能的）

The previous code doesn't work, you get tons of other errors. It's just not possible :)

它不工作不是因为你限制它创建 const 对象的副本，但是没有办法强制新创建的对象也是 const 。

It doesn't work not because you restrict it from creating copies of const objects, but there's no way to enforce that the newly created object is also const.

这篇关于force const存储由值返回的值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！