如何在默认构造函数中初始化引用成员？ [英] How can I initialise a reference member in the default constructor?

问题描述

问题说的一切真的。

如果我实现默认构造函数，最好使用const指针成员？

Would it be better to use const pointer members instead if I were to implement the default constructor?

推荐答案

您需要使用成员初始化列表：

You need to use the member initialization list:

struct foo
{
  const int& ref;
  foo() : ref(some_value()) { }
}

确保 some_value（）不会给你一个临时。它将只有它的生命延长到构造函数的结束：

Make sure some_value() doesn't give you a temporary. It will only have its life extended until the end of the constructor:

临时绑定到构造函数的ctor-initializer中的引用成员12.6.2）持续到构造函数退出。

A temporary bound to a reference member in a constructor’s ctor-initializer (12.6.2) persists until the constructor exits.

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