将多个变量打包成一个字符串 [英] Packing multiple variable into one string

问题描述

字符流被发送到通信设备。为了可读性，我将个人配置写为变量：

A stream of chars are sent out to a communication device. For readability purposes, i wrote inidividual configurations as variables:

unsigned char a1;
unsigned char a2;
unsigned char a3;
unsigned char a4;
unsigned char a5;
std::string a6;
unsigned char a7;
unsigned char a8;

什么是最好的方式将它包装到一个变量，使它完美对齐？
到现在我想到把一切都变成 struct 。

What is the best way to pack it into a variable tightly so that it's aligned perfectly? Till now I've think of put everything into a struct.

/ strong>： struct 看起来不像一个可行的选项，因为 struct 不支持 string ，并且字符串的大小是变化的，虽然是一次声明的东西。在GCC中编译

edit: struct doesn't look like a viable option since struct doesn't hold string, and string is varying in size, although is a one time declared thing. Compiled in GCC

edit2 ：使用打包的 struct 方法，首先将 string 更改为 c_str 。

edit2: Gonna go with packed struct method, but will convert the string to a c_str first. Until a better answer, this is the way to be.

推荐答案

A 打包结构 ，而不仅仅是一个结构会更合适。

A packed structure, rather than just a structure would be more appropriate.

编辑：当然，你不应该使用 string 作为你的结构的一部分，正如其他人所指出的。您应该使用 str.c_str（））; 将 string 转换为字符数组，然后将其存储在打包结构。

Ofcourse, you should not use string as a part of your structure, It skipped me while answering but as others have pointed out. You should conver string to character array using str.c_str()); and then store the same in the packed structure.

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