如何把循环变成一个数学方程？ [英] How to turn for loop into a math equation?

问题描述

我在程序中有以下两个循环，我想把它们写成数学方程，但是我有一些困难找到一个简单的方法：

I have the following two loops in my program and I am trying to write them out as math equations, but I'm having some difficulty finding a concise way to do so:

// Loop1
for (int i = 0; i < nr; i++) {
    array[i] = nepr;
}

// Loop2
for (int i = 0; i < (nvr % nr); i++) {
    array[i]++;
}

代码完全功能，但我试图表达这些循环我正在写的文档。

The code is completely function, but I'm trying to express these loops in a document I'm writing.

任何帮助将非常感激。

Any help would be very much appreciated.

到目前为止我有这个：

array[i] = nepr, i = 0,...,(nr-1)

但我不知道如何将第二个循环合并到方程式，第二个方程为它。

but I'm not sure how to incorporate the second loop into the equation, or write a second equation for it.

推荐答案

不完全清楚，这是你要求，但下面做同样的事情在一个

Not entirely clear that's what you are asking, but the following does the same thing in a single loop.

for (int i = 0, j = nvr % nr; i < nr; i++) {
    array[i] = nepr + (i < j);
}

---

以上等同于...

---

In casual language without any loops the above is equivalent to...

让 j = nvr％nr 。假设阳性 nr 和 nvr ， 0 <= j < nr 和：

• array [i] = nepr + 1 i = 0 ... j-1


• array [i] = nepr i = j ... nr-1

• array[i] = nepr + 1 for i = 0 ... j-1
• array[i] = nepr for i = j ... nr-1

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