删除矢量矢量内的重复矢量 [英] Remove duplicate vectors inside a vector of vector

问题描述

我有一个向量（ loops ），它包含整数值。一些内部矢量是重复的，但它们的元素顺序是不一样的。现在，我想得到一个矢量的矢量，没有任何重复的内部矢量。
这里是我vec vec的例子;

I have a vector of vector (loops) which contains integer values. Some inside vectors are duplicating but their element order is not the same. Now, I want to get a vector of vector without having any duplicate inner vectors. here is an example for my vec of vec;

loops =（（9 18 26 11 9），（9 11 26 18 9）， 18 25 16 9），（11 45 26 11），（11 26 45 11），（16 49 25 16），（16 25 49 16），（18 9 11 26 18）， （25 16 49 25），（26 11 45 26））

loops = ((9 18 26 11 9), (9 11 26 18 9),(9 18 25 16 9),(11 45 26 11),( 11 26 45 11),( 16 49 25 16),( 16 25 49 16),(18 9 11 26 18),( 18 9 16 25 18),( 25 16 49 25),( 26 11 45 26))

识别任何内部向量是否是另一个内部向量的副本;我开发了一个函数 IsDuplicate 。这告诉我，（9 18 26 11 9）和（9 11 26 18 9）是重复的，那么我可以删除第二个或所有其他重复。

To identify whether any inner vector is a duplicate of another inner vector; I have developed a function IsDuplicate. This tells me, (9 18 26 11 9) and (9 11 26 18 9) are duplicates then I can delete the second or all other duplicates.

为了删除我向量中的重复向量，我实现了以下代码。

To remove duplicate vectors inside my vector of vector, I have implemented following codes.

Vector<vector<int> > loops;
Vector<vector<int> > ::iterator no1, no2;
Int setno1, setno2;

for (no1=loops.begin(), setno1=0; no1!=loops.end(); no1++, setno1++){
       set1 = *no1;
       for (no2=loops.begin()+setno1, setno2=setno1; no2!=loops.end(); setno2++){
            set2 = *no2;
            if (set2.IsDuplicate(set1))  loops.erase(loops.begin()+setno2);
            else no2++;
       }

  }

我认为我的程序是crasihing。所以，请帮我纠正这个问题。

it took very very long time and i thought my program is crasihing. so, Please help me to rectify this issue.

也，我试过这个。这工作，但我有一个错误的答案。任何帮助。

also, i tried with this. this works but i got a wrong answer. any help please.

01   int first=0; bool duplicates=false;  
02   do {     
03        set1 = loops[first];     
04        for (no2=loops.begin()+1, setno2=1;  no2!=loops.end();  setno2++){     
05             set2 = *no2;      
06             if (set2.IsPartOf(set1)){      
07                 loops.erase(loops.begin()+setno2);     
08                 duplicates = true;      
09             }      
10             else no2++;     
11        }      
12        first++;      
13       } while(!duplicates); 

推荐答案

惯用的方法是使用使用自定义谓词删除/删除成语。
要检查重复的向量，而不修改向量的内容，写一个谓词，它接受其参数的值，排序向量，并使用 std :: equal 。

The idiomatic way is to use the Erase/Remove idiom with a custom predicate. To check for duplicate vectors and without modifying the contents of your vectors, write a predicate that takes its arguments by value, sort the vectors and use std::equal.

bool equal_vector(std::vector<int> a, std::vector<int> b) {
  std::sort(a.begin(), a.end());
  std::sort(b.begin(), b.end());

  return std::equal(a.begin(), a.end(), b.begin());
}

// use it like this
v.erase( remove_if(v.begin(), v.end(), equal_vector), v.end() );

为什么当前代码失败：从向量中删除元素使当前存在的那个向量的所有其他迭代器无效，因此 vector :: erase 返回一个有效的迭代器到已经删除的元素之后的位置。

As to why your current code fails: Erasing an element from a vector invalidates all other iterators to that vector that are currently in existence thus vector::erase returns a valid iterator to the position after the element that has been removed.

stdlib还提供 set 和 multiset 容器，看起来更适合您的目的。

The stdlib also provides the set and multiset container which look like a much better fit for your purpose.

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