CMake是否总是为所有可能的项目配置生成配置？ [英] Does CMake always generate configurations for all possible project configurations?

问题描述

我有调试和发布选项的具体配置（不同于MSVC和GCC）。假设我们通过 cmake .. 生成默认项目。 CMake总是生成所有可能的项目配置（Debug和Release）的配置，或者总是只得到一组配置选项？

解决方案

因为@cplusplusrat注释过，这取决于生成器/构建环境：

• 对于MSVC或XCode等多配置环境，是的。


配置环境既不是调试也不是发布（请参阅这里或这里）。




所以我一直定义一个 CMAKE_BUILD_TYPE 作为默认配置。您也可以执行此操作。在构建脚本中调用CMake：





mingw_build.cmd

 code> @ECHO off 
 SETLOCAL ENABLEDELAYEDEXPANSION 
 :: usage：
 :: mingw_build.cmd< target> < config& 
 ::< target> - 要构建的目标（默认：全部）
 ::< config> - 配置用于构建（默认：调试）
 
如果不是％1==（设置CMAKE_TARGET =％1）else（设置CMAKE_TARGET = all）
 ％2==（set CMAKE_BUILD_TYPE =％2）else（set CMAKE_BUILD_TYPE = Debug）
 SET CMAKE_BINARY_DIR =％CMAKE_BUILD_TYPE％
 
如果不存在％CMAKE_BINARY_DIR％\Makefile （
 cmake -H。-B％CMAKE_BINARY_DIR％-DCMAKE_BUILD_TYPE =％CMAKE_BUILD_TYPE％-GMinGW Makefiles
）
 cmake --build％CMAKE_BINARY_DIR％--target ％CMAKE_TARGET％
 
 ENDLOCAL 
  

vs_x64_build.cmd

  @ECHO off 
 SETLOCAL ENABLEDELAYEDEXPANSION 
 :: usage：
 :: vs_x64_build。 cmd< target> < config> 
 ::< target> - 要构建的目标（默认：ALL_BUILD）
 ::< config> - 如果不是％1==（SET CMAKE_TARGET =％1）else（SET CMAKE_TARGET = ALL_BUILD）
如果不使用，配置用于构建（默认：调试）
 $ b ％2==（set CMAKE_BUILD_TYPE =％2）else（set CMAKE_BUILD_TYPE = Debug）
 SET CMAKE_BINARY_DIR = x64 
 
如果不存在％CMAKE_BINARY_DIR％\ * .sln （
 cmake -H。-B％CMAKE_BINARY_DIR％-GVisual Studio 14 2015 Win64
）
 cmake --build％CMAKE_BINARY_DIR％--target ％CMAKE_TARGET％--config％CMAKE_BUILD_TYPE％
 
 ENDLOCAL 
  




I have specific configuration for debug and release options (diferent for MSVC and for GCC). Say we generate default project via cmake ... Does CMake always generate configurations for all possible project configurations (Debug and Release) or one always gets only one set of comfiguration options?

解决方案

As @cplusplusrat has commented, this depends on the generator/build environment:

• For multi-configuration environments like MSVC or XCode, yes.
• For single-configuration environments like GCC, no.

And the default for single-configuration environments is neither Debug nor Release (see here or here).

So I have always defined one CMAKE_BUILD_TYPE for single-configuration environments as a default. You could also do this e.g. in build scripts calling CMake:

mingw_build.cmd

@ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION
:: usage:
::          mingw_build.cmd <target> <config>
::                  <target> - target to be built (default: all)
::                  <config> - configuration to be used for build (default: Debug)

if NOT "%1" == "" (set CMAKE_TARGET=%1) else (set CMAKE_TARGET=all)
if NOT "%2" == "" (set CMAKE_BUILD_TYPE=%2) else (set CMAKE_BUILD_TYPE=Debug)
SET CMAKE_BINARY_DIR=%CMAKE_BUILD_TYPE%

IF NOT EXIST "%CMAKE_BINARY_DIR%\Makefile" (
    cmake -H"." -B"%CMAKE_BINARY_DIR%" -DCMAKE_BUILD_TYPE=%CMAKE_BUILD_TYPE% -G"MinGW Makefiles"
)
cmake --build %CMAKE_BINARY_DIR% --target %CMAKE_TARGET%

ENDLOCAL 

vs_x64_build.cmd

@ECHO off
SETLOCAL ENABLEDELAYEDEXPANSION
:: usage:
::          vs_x64_build.cmd <target> <config>
::                  <target> - target to be built (default: ALL_BUILD)
::                  <config> - configuration to be used for build (default: Debug)

if NOT "%1" == "" (SET CMAKE_TARGET=%1) else (SET CMAKE_TARGET=ALL_BUILD)
if NOT "%2" == "" (set CMAKE_BUILD_TYPE=%2) else (set CMAKE_BUILD_TYPE=Debug)
SET CMAKE_BINARY_DIR=x64

IF NOT EXIST "%CMAKE_BINARY_DIR%\*.sln" (
    cmake -H"." -B"%CMAKE_BINARY_DIR%" -G"Visual Studio 14 2015 Win64"
)
cmake --build "%CMAKE_BINARY_DIR%" --target "%CMAKE_TARGET%" --config "%CMAKE_BUILD_TYPE%"

ENDLOCAL 

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