什么是“引用永远不能指向另一个对象”意思？ [英] What does "reference can never be made to refer to another object" mean?

问题描述

我读了关于C ++引用变量和某处我发现这个：

一个const引用的声明是多余的，因为引用永远不能

这里，例如，我可以改变引用指向的对象：

  void p（int& i）{
 int a = 7，c = 0; 
 i = a; 
} 
  

因此，参考永远不能指向另一个

解决方案

这意味着，给定此代码

  int a; 
 int b; 
 int& ref = a; 
  

一旦你初始化了 ref 指向 a ，没有办法让它引用 b 或任何其他变量。

对引用所做的任何更改都将反映在用于初始化它的变量上。引用（它本身不是一个合适的对象）保持不变。

引用只有在它引用的对象保持活动时才可用。 p>

I read about C++ reference variables and somewhere I found this:

A declaration of a const reference is redundant since reference can never be made to refer to another object.

what does it mean?

Here, for example, I can change the object that the reference is referring to:

void p(int& i) {
    int a = 7,c = 0;
    i = a;
}

So what does it mean that "Reference can never be made to refer to another object"?

thanks in advance.

解决方案

It means, given this code

int a;
int b;
int& ref = a;

that, once you've initialized ref to refer to a, there is no way you can make it refer to b or any other variable.

Any change you make to the reference will reflect on the variable that you used to initialize it with. The reference (which itself is not even a proper object) stays intact.

Also, a reference is only usable as long as the object it refers to stays alive.

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