如何从向量中删除struct元素？ [英] How to remove a struct element from a vector?

问题描述

我是一个新手程序员，我正在一个程序，在一个酒店（在我们在课堂上看到的一些愚蠢的运动，注册表）没有关系。我使用向量来保存结构元素（宠物）。结构的代码如下：

I'm a newbie programmer and I'm working on a program that holds a registry of pets in a hotel (some silly exercise we saw in class, doesn't matter). I'm using vectors for holding the struct elements (pets). The code for the struct is this:

struct Pets{
string Name;
string Race;
string Owner;
int Tel;
}p;

要求用户输入的功能是：

And the function to ask for user input is this:

AddPet(vector<Pets> &vtnew)
{
Pets newpet;
cout << "Enter the pet's name: " << endl;
cin >> newpet.Name;
cout << "Enter the pet's race: " << endl;
cin >> newpet.Race;
cout << "Enter the owner's name: " << endl;
cin >> newpet.Owner;
cout << "Enter the owner's telephone number: " << endl;
cin >> newpet.Tel;
vtnew.push_back(newpet);
}

好，现在我需要创建一个函数来删除宠物名称或某事。有没有办法做到这一点？

Ok, now I need to create a function to remove the pet by entering the name or something. Is there any way to do that?

推荐答案

向量是一个未排序的容器，所以简单的解决方案是真正唯一的选择。 / p>

A vector is an unsorted container so the simple solutions are really your only choice.

void RemovePet(std::vector<Pet> & pets, std::string name) {
    pets.erase(
        std::remove_if(pets.begin(), pets.end(), [&](Pet const & pet) {
            return pet.Name == name;
        }),
        pets.end());
}

这称为 Erase-remove idiom 。

请注意，这会删除所有与该名称相符的宠物，不只是一个。

Note that this will remove all pets matching that name, not just one.

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