如何在刷新`std :: cin`的内容之前再读一遍？ [英] How do you flush the contents of `std::cin` before an additional read from it?

问题描述

我想多次读取单个字符。抓住的是，我需要防止用户错误。例如：

I am trying to read a single character multiple times. The catch is that I need to prevent user errors. So for example:

char arr[10];
for(int i = 0; i < 10; i++)
{
    cin.get(arr[i]);
} 

输入应该是 a，b ，c，d，... 。但如果有人要为第一个条目输入 ab ，我想捕获 a ，然后忽略 b 。我知道 cin.ignore 但是我不知道我会忽略任意数量的字母数字字符或符号，因为我想忽略一个潜在的无限数量然后停止忽略并重新读取。

Where the inputs should be something like a, b, c, d, .... But if someone were to enter ab for the first entry I want to capture the a and then ignore the b. I know about cin.ignore however I don't know how I would go about ignoring an arbitrary number of alphanumeric characters or symbols considering that I want to ignore a potentially unlimited number of characters and then stop ignoring and read again.

如何忽略任意数量的字符，然后停止忽略或清除cin的缓冲区。

How can I either ignore an arbitrary number of characters and then stop ignoring or how can I actually flush the buffer for cin.

推荐答案

大多数输入都是换行符，所以如果你想忽略输入流中的所有字符，使用：

Most input is line feed so if you want to ignore all characters in the input stream until you hit a newline then you could use:

std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n')

由于我们忽略 streamsize 在输入缓冲区中不应有额外的内容。

Since we ignore up to the streamsize there should not be an extra content in the input buffer.

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