从分割字符串定义变量？ [英] Defining variables from split strings?

问题描述

例如

$

b $ b

  Workspace.Hello.Hey将打印为WorkspaceHelloHey
  

但是，我需要知道如何定义它们作为自己的SEPARATE变量，稍后可以调用。
这是我有的代码。

  std :: string str; 
 std :: cin>> str; 
 std :: size_t pos = 0，tmp; 
 while（（tmp = str.find（'。'，pos））！= std :: string :: npos）{
 str [tmp] ='\0' 
 std :: cout<< 获得<< str.substr（pos）<  然后 ; 
 pos = tmp; 
} 
 std :: cout<< 获得<< str.substr（pos）<  然后 ; 
  

解决方案

将子字符串放在向量中。这里有一个例子：

  std :: string str; 
 std :: cin>> str; 
 std :: size_t pos = 0，tmp; 
 std :: vector< std :: string>值; 
 while（（tmp = str.find（'。'，pos））！= std :: string :: npos）{
 values.push_back（str.substr（pos，tmp  -  pos）） ; 
 pos = tmp + 1; 
} 
 values.push_back（str.substr（pos，std :: string :: npos））; 
 
 for（pos = 0; pos< values.length（）; ++ pos）
 {
 std :: cout< 字符串部分<< pos < is<<值[pos] std :: endl; 
} 
  

So, I've made this code, and it basically splits up the users input into different strings.

For example

Workspace.Hello.Hey would then be printed out as "Workspace" "Hello" "Hey"

However, I need to know how to define each of those as their own SEPARATE variable that can be called later on. This is the code I have.

std::string str;
    std::cin >> str;
    std::size_t pos = 0, tmp;
    while ((tmp = str.find('.', pos)) != std::string::npos) {
        str[tmp] = '\0';
        std::cout << "Getting " << str.substr(pos) << " then ";
        pos = tmp;
    }
    std::cout << "Getting " << str.substr(pos) << " then ";

解决方案

Put the substrings in a vector. Here's an example:

std::string str;
std::cin >> str;
std::size_t pos = 0, tmp;
std::vector<std::string> values;
while ((tmp = str.find('.', pos)) != std::string::npos) {
    values.push_back(str.substr(pos, tmp - pos));
    pos = tmp + 1;
}
values.push_back(str.substr(pos, std::string::npos));

for (pos = 0; pos < values.length(); ++pos)
{
    std::cout << "String part " << pos << " is " << values[pos] << std::endl;
}

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