qt如何知道一个按钮被点击？ [英] qt how to know that a pushbutton is clicked?

问题描述

我试图做一个程序，使一些操作与声音。我的问题是，我有3播放按钮和3标签。我想要的，无论我单击播放按钮，声音的名称是在按钮附近的标签应该播放。
我有一个播放插槽没有任何参数。那么，我如何分别连接到每个播放按钮与每个标签？其实，我可以写3个不同的播放功能，但由于我有一些其他功能，它会太长和混乱。

I'm trying to do a program which makes some operations with sounds. My question is that I have 3 Play pushbutton and 3 label. I want that whichever I click on the Play button, the sound whose name is in the label that is near the pushbutton should play. I have a play slot without any parameter. So, how can I connect to every play button with every label respectively? Actually, I can write 3 different play function, but since I have some other functions, it will be too long and confusing. Also, I need 3 play button because I want to play 3 sounds simultaneously.

推荐答案

例如，通过连接 发出所有按钮到插槽的信号，然后使用 QObject :: sender（） 找出它是哪个按钮。

For example by connecting the clicked signal from all the buttons to a slot, and then use QObject::sender() to find out which button it was.

让我们假设您的按钮分别命名为 pushButton，pushButton_2 和 pushButton_3 和标签 label，label_2

Let's assume your buttons are named pushButton, pushButton_2 and pushButton_3 and labels label, label_2 and label_3 respectively.

MainWindow::MainWindow(QWidget *parent) :
    QMainWindow(parent),
    ui(new Ui::MainWindow)
{
    ui->setupUi(this);
    connect(ui->pushButton, SIGNAL(clicked()), this, SLOT(play()));
    connect(ui->pushButton_2, SIGNAL(clicked()), this, SLOT(play()));
    connect(ui->pushButton_3, SIGNAL(clicked()), this, SLOT(play()));
}

void MainWindow::play()
{
    QString piece;
    QObject* button = QObject::sender();
    if (button == ui->pushButton)
    {
        piece = ui->label->text();
    }
    else if (button == ui->pushButton_2)
    {
        piece = ui->label_2->text();
    }
    else
    {
        piece = ui->label_3->text();
    }

    qDebug() << "Starting to play:" << piece;
}

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