将hex缓冲区转换为unsigned int [英] convert hex buffer to unsigned int

问题描述

我一直在尝试将保存在缓冲区中的十六进制数转换为unsigned int。然而，在我读取的每个十六进制数字前面的0x00一直给我的问题，本质上，问题（在缩减版本）看起来像这样：

I've been trying to convert a hexadecimal number saved in a buffer to an unsigned int. However the "0x00" in front of every hexadecimal number that I'm reading from has been giving me problem, in essence the problem (in a downscaled version) looks like this:

char b[] = "0x0014A12";
std::stringstream ss;
unsigned int i;
ss << std::hex << b;
ss >> i;
cout << i << endl;

任何提示？

注意：程序输出一个高十进制的小数，等于十六进制的CCCCCC。

Note: The program outputs a high decimal nubmer which equals CCCCCC in hex.

推荐答案

这对我来说很好：

#include <iostream>
#include <sstream>

int main(int argc, char* argv[])
{
    using namespace std;

    string b("0x0014A12");

    stringstream ss;
    ss << hex << b;

    unsigned int dec;
    ss >> dec;

    cout << b << " = " << dec << endl;
    return 0;
}

输出：

0x0014A12 = 84498

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