在return语句中取消引用的指针会发生什么？ [英] What happens to a pointer dereferenced in the return statement?

问题描述

这是与作业相关的问题。这不是我完成的作业本身。

This is a question related to homework. It is not the homework itself, which I have completed.

这里是一个函数的一部分（我认为相关的唯一的部分）。

Here's part of a function (the only pieces that I think relevant).

double mean(double* pD, int* sz) {
    double *meanPtr = new double;
    *meanPtr = 0.0;
    return *meanPtr; //how to deal with a memory leak in return statement? does it leak?
}

我关心最后一位。这是否会导致内存泄漏，因为我没有指向null或删除指针？

I'm concerned about the last bit. Does this result in a memory leak as I haven't pointed to null or deleted the pointer?

推荐答案

如果你需要解决正是这个问题比这样。

If you need to solve exactly this problem than do like this

double mean(double* pD, int* sz) {
    double mean = 0.0;
    return mean;
}

如果这只是一个例子，你需要使用指针，指针。您可以将它包装在 std :: shared_ptr 中，以防止手动内存控制。

If this is just an example and you need to use pointers, then return a pointer. You can wrap it in std::shared_ptr to prevent manual memory control.

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