在c ++中从一行输入读取多个命令 [英] Reading multiple commands from one line of input in c++

问题描述

说出输入可以是'x'，'y'和'z'，并且对于每个commandX（），commandY（）和commandZ（）可以分别执行。而不是必须键入，然后按enter键每次（即：x（enter）commandX（）执行然后y（enter）commandY（）执行...）我如何让用户输入它只有一行（即：xyz （enter）），然后命令按照它们的输入顺序连续进行？ （即：在x，y，z中，执行顺序将是commandX（）then commandY（）then commandZ（））

解决方案

p>您最有可能需要 getopt 。 p>

然而，你可以用while循环来实现相同的结果 - 害羞的一些功能 -

  unsigned int i（1）; 
 bool run_x（false），run_y（false），run_z（false）; 
 
 while（i  
 switch（argv [i + 1]）{
 
 case'x'：
 run_x = true; 
 i + = 2; 
 break; 
 
 case'y'：
 run_y = true; 
 y_value = argv [i + 1]; 
 i + = 3; 
 break; 
 
 case'z'：
 run_z = true; 
 i + = 2; 
 break; 
 
} 
 
} 
  

的程序可以执行如下：

  ./ program -x -y 10 -z 
 ./program  - x -z 
 ./program -z 
 ./program -y 10 -z 
 ... 
  

使用布尔值和其他变量来控制/是不是可选的。

Say input can be 'x','y' and 'z' and for each commandX(),commandY() and commandZ() can be executed, respectively. Instead of having to type then pressing enter each time (ie: x (enter) commandX() executed then y (enter) commandY() executed ...) how can I let the user input it into just one line (ie: x y z (enter)) and then the commands are made consecutively in the order of their input? ( ie: in x , y , z the order of execution will be commandX() then commandY() then commandZ())

解决方案

You are most probably looking for getopt.

Yet, you can achieve the same result -- being shy some features --, with a while loop:

unsigned int i(1);
bool run_x(false), run_y(false), run_z(false);

while (i < argc and argv[i] == '-') {

    switch (argv[i + 1]) {

        case 'x':
            run_x = true;
            i += 2;
            break;

        case 'y':
            run_y = true;
            y_value = argv[i + 1];
            i += 3;
            break;

        case 'z':
            run_z = true;
            i += 2;
            break;

     }

}

And the execution of the program could be performed like:

./program -x -y 10 -z
./program -x -z
./program -z
./program -y 10 -z
...

Use the booleans and other variables to control what is/is not optional.

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