从C ++中的文件读取 [英] Read from a file in C++

问题描述

4;

Spadina; 76 156

Bathurst; 121 291

Keele; 70 61

Bay; 158 158 < br>

4;
Spadina;76 156
Bathurst;121 291
Keele;70 61
Bay;158 158

这是文件包含的内容。我需要读取它们并将它们保存为变量。

This is what file contains in it. I need to read them and save them into variables.

4用于动态内存分配。 4表示有4个站。
Spadina，Bathrust等。他们是车站名。第一个数字，紧接车站名称后，是学生通行证的数量，第二个数字是成人通行证的数量。

4 is for dynamic memory allocation. 4 means there are 4 stations. Spadina, Bathrust, etc.. they are station names. first number, which comes right after station names, is number of student passes and the second number is number of adult pass.

因此，基本上我有4个变量，它们是：

So, basically I have 4 variables and they are;

int numberOfStation;
int studentPass;
int adultPass;
string stationName;

我花了4小时，但仍然无法读取文件并将其保存到变量

。谢谢。

I spent 4 hours but still cannot read the file and save it into variable
Thank you.

推荐答案

首先将您的变数分组。

struct MyStruct
    {
        int studentPass;
        int adultPass;
        string stationName;
    };

现在读取文件中struct的大小并动态分配。

Now read size of struct in file and allocate it dynamically

MyStruct *p;

s >> N;
p = new MyStruct[N];

现在在for循环中，您读取的字符串使用分隔符';'和其他两个vars是int

Now in for loop you read string with delimiter ';' and other two vars are ints

for (int i = 0; i < N; i++)
{
    getline(s, p[i].stationName, ';');
    s >> p[i].studentPass >> p[i].adultPass;
}

其中var s 是istream类型的变量，标志 std :: in

Where var s is istream type of variable with flag std::in

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