错误：无法将参数1从std :: string转换为char *。困惑为什么它给我这个错误。 [英] Error: Cannot convert parameter 1 from std::string to char*. Confused on why it is giving me this error.

问题描述

所以我再次需要一些帮助这个程序的类。也许它，我累了，但我似乎找不到逻辑错误，我相信我在这里。这是我的代码：

So once again I need some help with this program for class. Maybe its that I'm tired but I can't seem to find the logic error I'm sure I've made here. Here is my code:

#include "Book.h"


using namespace std;

void add (char*, char*, int);
void remove (int&);
void list ();

int Count;

Book Bookshelf [4];

int main ()
{   
    string In;
    string N;
    string A;
    int Y;
    int Num;

    do
    {
        cout << "Bookshelf> ";
        getline(cin, In);

        if (In.compare("add") == 0)
        {
            cout << "Bookshelf> Enter book: ";
            cin >> N >> A >> Y;
            add (N,A,Y);
        }

        else if (In.compare ("remove") == 0)
        {
            cout << "Bookshelf> Select number: ";
            cin >> Num;
            remove (Num);
        }

        else if (In.compare("list") == 0)
        {
            list ();
        }

    } while (cin != "quit");

    return 0;
}

void add (string N, string A, int Y)
{
    if (Bookshelf[4].IsEmpty() == false)
        cout << "Error!" << endl;
    else
    {
        Bookshelf[Count] = Book (N,A,Y);
        Count++;
    }
    cout << "Bookshelf> ";
}

错误发生在 add A，Y）; 但对于我的生活我不知道为什么这么说。他们看起来像std ::字符串给我。

The error occurs at the line add(N,A,Y); but for the life of me I can't tell why it is saying that. They both look like std::strings to me. Can anyone explain this to me?

推荐答案

您忘了在文件顶部修改原型。

You have forgotten to modify your prototype at the top of your file.

它仍然说

void add (char*, char*, int);

应为

void add (string, string, int);

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