使用getche（）函数的C ++短语计数器 [英] C++ phrase counter with getche() function

问题描述

#include<iostream>
using namespace std;
#include<conio.h>

int main()
{

int chcount = 0, wdcount =0, count = 0;
char ch='a';

cout << "Enter your text : ";
while ( ch != '\r' )
 {
      ch = getche();
      if ( ch !=' ' )
      {
           chcount++;
           count++;          
      }
      else if (count > 2)
           {
                    wdcount++;
                    count=0;
           }
  }


  cout<<"\nCount of words is: "<<wdcount+1<<"\nCount of charcters is: "<<chcount-1<<"\n";

system("pause");
return 0;}

此代码计算大小大于两个字符的字词，用户输入的短语中的所有字符数（忽略空格）。问题是为什么字计数器初始值被认为+1，字符计数器初始值被认为-1（你可以看到cout wdcount + 1和chcount-1）？

this code counts the words with size greater than two characters and the number of all characters (ignore spaces) in a phrase typed in by the user. The question is why the word counter initial value is considered +1 and character counter initial value considered -1 (as you can see the cout wdcount+1 and chcount-1)?

推荐答案

在一些尝试后，我终于得到了正确的答案，我喜欢发布它来帮助任何人感兴趣...感谢所有为您的帮助

After some tries I finally got the correct answer I liked to post it to help anyone interested .. thanks all for your help

#include<iostream>
using namespace std;
#include<conio.h>

int main()
{


int chcount = 0, wdcount =0, count = 0;
char ch=' ';

cout << "Enter your text : ";

while ( ch != '\r' )
 {

      if ( ch !=' ' )
      {
           chcount++;
           count++;      
      }
      else if (count > 2)
           {
                    wdcount++;
                    count=0;             
           }
   ch = getche();
  }

  if (count >2)  //validate that last word is counted
  wdcount++;

  cout<<"\nCount of words is: "<<wdcount<<"\nCount of charcters is: "<<chcount<<"\n";

 system("pause");
 return 0;

}

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