为什么是这个NaN [英] Why is this NaN

问题描述

我想运行以下代码

  int salespersons = 0，weeks = 0，days = 5; 
 
 double weekly_sales [weeks] [salesperson] [days]; 
 double total_weekly_sales [weeks]; 
 
 
 for（int w = 0; w  {
 for（int d = 0; d< days; d ++）
 {
 
 for（int s = 0; s< salespersons; s ++）
 {
 
 {
 total_weekly_sales [w] + = weekly_sales [w] [s] [d]; 
 total_overall_weekly_sales [s] + = weekly_sales [w] [s] [d]; 
 
} 
} 
} 
 
} 
  

当我只运行..

  cout< total_weekly_sales [0]; 
 

因此，NaN在处理数组时跳过数组的第一部分。

解决方案

  double weekly_sales [weeks] [salespersons] [days] 
 double total_weekly_sales [weeks]; 
  

未初始化。 b
$ b

编辑：这是您应如何初始化它们：

  double weekly_sales [weeks] salespersonons] [days] = {{{0.0}}}; 
  




Im trying to run the following code

  int salespersons=0,weeks=0,days=5;

  double weekly_sales[weeks][salespersons][days];
  double total_weekly_sales[weeks];


for(int w=0; w < weeks;w++)
  {
     for(int d =0; d < days; d++)
     {  

        for(int s=0; s < salespersons; s++)
        {

           {
              total_weekly_sales[w]+=weekly_sales[w][s][d];
              total_overall_weekly_sales[s]+= weekly_sales[w][s][d];

           }
        }  
     }

  }

when I run only..

cout << total_weekly_sales[0];

I get NaN therefore skipping the first section of the array while processing the rest.

解决方案

double weekly_sales[weeks][salespersons][days];
double total_weekly_sales[weeks];

Uninitialized.

Edit: this is how you should initialize them:

double weekly_sales[weeks][salespersons][days] = { { { 0.0 } } };

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