类的operator()或绑定函数作为函子? [英] Class's operator() or bind a function as a functor?
本文介绍了类的operator()或绑定函数作为函子?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有两种方法可以创建一个函数(一个保存状态的函数):
There are two ways to make a functor (a function that holds a state):
-
绑定函数并定义一个状态:
bind(f,_1,state)
double g(double x,double state){
return x + state;
}
function f = bind(g,_1,state);
double g(double x, double state) { return x+state; } function f = bind(g,_1,state);
use code>运算符和类:
use ()
operator and a class:
struct f {
double state;
f(double state_):state(state_) {}
double operator()(double x) {return x+state;}
};
我发现 bind
写作,但我想知道是否有一些隐藏的石头,因为大多数时间在文学中我看到函子作为类的()
运算符。
I find that bind
-method is faster to write but I'm wondering if there are some hidden stones since most of the time in literature I see functor as class's ()
operator.
推荐答案
3.方式是一个lambda表达式:
The 3. way is a lambda expression:
auto f = [state]( double x ) { return x * state; };
这篇关于类的operator()或绑定函数作为函子?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文