从阿贾克斯装型号后AngularJS更新视图 [英] AngularJS update View after Model loaded from Ajax

查看:134
本文介绍了从阿贾克斯装型号后AngularJS更新视图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我angularjs开发的新手,我写了这个简单的应用程序,但不明白我怎么可以更新视图,模型IL后,从启动Ajax请求加载!

这code不要当我添加延迟到photos.php使用工作,:     睡眠(3); 为模拟远程服务器延迟!反而如果search.php中是快速它的工作!

 <!DOCTYPE HTML>
< HTML NG-应用程序=photoApp>
< HEAD>
<冠军>图片< /标题>
< /头>
<身体GT;
    < D​​IV NG-视图>< / DIV>

<脚本的src =../ angular.min.js>< / SCRIPT>
<脚本>
使用严格的;

变种照片= []; //模型

VAR photoAppModule = angular.module('photoApp',[]);

photoAppModule.config(函数($ routeProvider){
    $ routeProvider.when('/照片,{
                        templateUrl:照片list.html,
                        控制器:listctrl的'});
    $ routeProvider.otherwise({redirectTo:/照片});
})
.RUN(函数($ HTTP){
    $ http.get('photos.php')//负荷延迟模型
    .success(函数(JSON){

        照片= json的; ///问题就在这里!如果photos.php慢不更新的观点!

    });
})
.controller('的listctrl',函数($范围){

    $ scope.photos =照片;

});
< / SCRIPT>
< /身体GT;
< / HTML>
 

photos.php的输出

  [{文件:cat.jpg,说明:我的猫在我家},
 {文件:house.jpg,说明:我的房子},
 {文件:sky.jpg并将,说明:天上掌管我的家}]
 

照片list.html

 < UL>
  <李NG重复=照片中的照片>
    < A HREF =#/照片/ {{$指数}}>
        < IMG NG-SRC =图像/拇指/ {{photo.file}}ALT ={{photo.description}}/>
    &所述; / a取代;
  < /李>
< / UL>
 

修改1,推迟解决办法:

  .RUN(函数($ HTTP,$ Q){

    VAR推迟= $ q.defer();

    $ http.get('photos.php')//负荷延迟模型
    .success(函数(JSON){
        执行console.log(JSON);

        照片= json的; ///问题!!如果photos.php慢不更新的观点!

        deferred.resolve(JSON); //解决方案!
    });

    照片= deferred.promise;
})
 

编辑2,服务的解决方案:

  ...
//需要角resource.min.js
angular.module('photoApp.service',['ngResource'])。厂(photoList',函数($资源){
    VAR RES = $资源('photos.php',{},
        {
            查询:{方法:GET,则params:{},IsArray的:真正}
        });
    返回水库;
});

变种photoAppModule = angular.module('photoApp',['photoApp.service']);

...

.RUN(函数($ HTTP,photoList){

    照片= photoList.query();
})
...
 

解决方案

简短的回答是这样的:

  .controller('的listctrl',['$范围,$超时',函数($范围,$超时){
    $超时(函数(){
        $ scope.photos =照片;
    },0);
}]);
 

长的答复是:请不要混合使用常规的JavaScript和角度是这样的。重新编写code,这样棱角分明知道什么是在任何时候都怎么回事。

  VAR photoAppModule = angular.module('photoApp',[]);

photoAppModule.config(函数($ routeProvider){
    $ routeProvider.when('/照片,{
        templateUrl:照片list.html,
        控制器:'的ListCtrl
    });

    $ routeProvider.otherwise({redirectTo:/照片});
});

photoAppModule.controller('的listctrl',['$范围',函数($范围){
    $ scope.photos = {};

    $ http.get('photos.php')//负荷延迟模型
        .success(函数(JSON){
            $ scope.photos = json的; //没有更多的问题
        });
}]);
 

I'm newbie of angularjs developing and i wrote this simple app, but don't understand how i can update view, after the model il loaded from ajax request on startup!

This code don't work when I add delay into photos.php, using: sleep(3); for simulate remote server delay! instead if search.php is speedy it work!!

<!doctype html>
<html ng-app="photoApp">
<head>
<title>Photo Gallery</title>
</head> 
<body>
    <div ng-view></div>

<script src="../angular.min.js"></script>
<script>
'use strict';

var photos = [];  //model

var photoAppModule = angular.module('photoApp', []);

photoAppModule.config(function($routeProvider) {
    $routeProvider.when('/photos', {
                        templateUrl: 'photo-list.html',
                        controller: 'listCtrl' });
    $routeProvider.otherwise({redirectTo: '/photos'});
})
.run(function($http) {
    $http.get('photos.php')//load model with delay
    .success(function(json) {

        photos = json; ///THE PROBLEM HERE!! if photos.php is slow DON'T update the view!

    });
})
.controller('listCtrl', function($scope) {

    $scope.photos = photos;

});
</script>
</body>
</html>

output of photos.php

[{"file": "cat.jpg", "description": "my cat in my house"},
 {"file": "house.jpg", "description": "my house"},
 {"file": "sky.jpg", "description": "sky over my house"}]

photo-list.html

<ul>
  <li ng-repeat="photo in photos ">
    <a href="#/photos/{{ $index }}">
        <img ng-src="images/thumb/{{photo.file}}" alt="{{photo.description}}" />
    </a>
  </li>
</ul>

EDIT 1, Defer solution:

.run(function($http, $q) {

    var deferred = $q.defer();

    $http.get('photos.php')//load model with delay
    .success(function(json) {
        console.log(json);

        photos = json; ///THE PROBLEM!! if photos.php is slow DON'T update the view!

        deferred.resolve(json);//THE SOLUTION!
    });

    photos = deferred.promise;
})

EDIT 2, Service solution:

... 
//require angular-resource.min.js
angular.module('photoApp.service', ['ngResource']).factory('photoList', function($resource) {
    var Res = $resource('photos.php', {},
        {
            query: {method:'GET', params:{}, isArray:true}
        });
    return Res;
});

var photoAppModule = angular.module('photoApp', ['photoApp.service']);

...

.run(function($http, photoList) {

    photos = photoList.query();
})
...

解决方案

The short answer is this:

.controller('listCtrl', ['$scope', '$timeout', function($scope, $timeout) {
    $timeout(function () {
        $scope.photos = photos;
    }, 0);
}]);

The long answer is: Please don't mix regular javascript and angular like this. Re-write your code so that angular knows what's going on at all times.

var photoAppModule = angular.module('photoApp', []);

photoAppModule.config(function($routeProvider) {
    $routeProvider.when('/photos', {
        templateUrl: 'photo-list.html',
        controller: 'listCtrl' 
    });

    $routeProvider.otherwise({redirectTo: '/photos'});
});

photoAppModule.controller('listCtrl', ['$scope', function($scope) {
    $scope.photos = {};

    $http.get('photos.php') // load model with delay
        .success(function(json) {
            $scope.photos = json; // No more problems
        });
}]);

这篇关于从阿贾克斯装型号后AngularJS更新视图的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆