CakePHP自定义路由类 - 如何传递参数？ [英] CakePHP Custom Route Classes - How to Pass Arguments?

问题描述

我创建了一个自定义路由类，我想能够传递设置/选项到构造函数，使其可配置。可以这样做吗？

自定义路由类的文档：

http://book.cakephp.org/2.0/en/development /routing.html#custom-route-classes

我的自定义路由类：

https://github.com/Signified/CakePHP-Model-Route -Class

解决方案

您可以只传递路由器选项中可能有的任何设置/选项： ：connect function。

  App :: import（'Lib'，'ModelRoute'）; 
 Router :: connect（'/'，array（'controller'=>'pages'，'action'=>'display'），
 Array（'routeClass'=>'ModelRoute '，
'someMoreOptions'=>'OptionValue'））;然后你可以在你的构造函数中检索一些关键字someMoreOptions 
 
 
 
 
 
 
 
 
 $ b b 
  public function __construct（$ settings = array（））
 {
 $ this-> settings = Set :: merge（$ this->设置，$设置）; 
 //现在你可以使用传递的选项做一些事情。 
 if（isset（$ this-> settings ['someMoreOptions']）
 DoSomethingWith（$ this-> settings ['someMoreOptions']）; 
} 
  
 
I've created a custom route class and I want to be able to pass in settings/options to the constructor so that it's configurable. Can this be done?


Documentation for Custom Route Classes:

http://book.cakephp.org/2.0/en/development/routing.html#custom-route-classes

My custom route class:

https://github.com/Signified/CakePHP-Model-Route-Class
解决方案
You can probably just pass any settings/options you might have in the options of your Router::connect function.
App::import('Lib', 'ModelRoute');
Router::connect('/', array('controller' => 'pages', 'action' => 'display'),
    Array('routeClass' => 'ModelRoute',
          'someMoreOptions' => 'OptionValue' ));
Then you can retrieve the key someMoreOptions in your constructor 
public function __construct($settings = array())
    {
        $this->settings = Set::merge($this->settings, $settings);
        // Now you can do something with the option passed.
        if(isset($this->settings['someMoreOptions'])
            DoSomethingWith($this->settings['someMoreOptions']);
    }


                        
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