返回给定年份的复活节日期的函数 [英] Function to return date of Easter for the given year

问题描述

所以，这里有一个有趣的小编程挑战。我正在写一个快速方法来确定特定年份的所有市场假日，然后我开始阅读复活节，并发现只是多么疯狂*的逻辑是确定其日期 - 在 Paschal满月之后的第一个星期日后春分！有没有人知道一个现有的函数来计算一个给定年份的复活节日期？

So, here's a funny little programming challenge. I was writing a quick method to determine all the market holidays for a particular year, and then I started reading about Easter and discovered just how crazy* the logic is for determining its date--the first Sunday after the Paschal Full Moon following the spring equinox! Does anybody know of an existing function to calculate the date of Easter for a given year?

授予，可能不是 ;我只是想我会问，如果有人已经这样做。 （这似乎很可能。）

Granted, it's probably not all that hard to do; I just figured I'd ask in case somebody's already done this. (And that seems very likely.)

UPDATE ：实际上，我真的在寻找 strong>（星期五之前的复活节）...我只是想了复活节会让我在那里。因为我在美国，我想我在寻找天主教复活节？但是如果我错了，也许有人可以纠正我。

UPDATE: Actually, I'm really looking for the date of Good Friday (the Friday before Easter)... I just figured Easter would get me there. And since I'm in the U.S., I assume I'm looking for the Catholic Easter? But perhaps someone can correct me on that if I'm wrong.

_{*疯狂我的意思， 。没有任何进攻...}

推荐答案

在SQL Server复活节星期天看起来像这样，

in SQL Server Easter Sunday would look like this, scroll down for Good Friday

CREATE FUNCTION dbo.GetEasterSunday 
( @Y INT ) 
RETURNS SMALLDATETIME 
AS 
BEGIN 
    DECLARE     @EpactCalc INT,  
        @PaschalDaysCalc INT, 
        @NumOfDaysToSunday INT, 
        @EasterMonth INT, 
        @EasterDay INT 

    SET @EpactCalc = (24 + 19 * (@Y % 19)) % 30 
    SET @PaschalDaysCalc = @EpactCalc - (@EpactCalc / 28) 
    SET @NumOfDaysToSunday = @PaschalDaysCalc - ( 
        (@Y + @Y / 4 + @PaschalDaysCalc - 13) % 7 
    ) 

    SET @EasterMonth = 3 + (@NumOfDaysToSunday + 40) / 44 

    SET @EasterDay = @NumOfDaysToSunday + 28 - ( 
        31 * (@EasterMonth / 4) 
    ) 

    RETURN 
    ( 
        SELECT CONVERT 
        (  SMALLDATETIME, 
                 RTRIM(@Y)  
            + RIGHT('0'+RTRIM(@EasterMonth), 2)  
            + RIGHT('0'+RTRIM(@EasterDay), 2)  
    ) 
END 
GO

strong> Good Friday 就是这样，它使用上面的复活节功能

Good Friday is like this and it uses the Easter function above

CREATE FUNCTION dbo.GetGoodFriday 
( 
    @Y INT 
) 
RETURNS SMALLDATETIME 
AS 
BEGIN 
    RETURN (SELECT dbo.GetEasterSunday(@Y) - 2) 
END 
GO

从这里开始：http://sqlserver2000.databases.aspfaq.com/why-should-i-consider-using-an -auxiliary-calendar-table.html

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