Codeigniter传递2个参数到回调 [英] Codeigniter passing 2 arguments to callback

问题描述

发布包含两个字段id和url的表单后，我有以下代码：

After posting a form having two fields named 'id' and 'url' I have the following code:

$this->load->library('form_validation');
$this->form_validation->set_rules('id', 'id', 'trim|xss_clean');
$this->form_validation->set_rules('url', 'url|id', 'trim|xss_clean|callback_url_check');

db查询需要这两个字段。

A db query needs both fields.

调用函数url_check（$ str，$ id），但在这种情况下，'id'总是为0.

The function url_check($str, $id) is called but in this case 'id' always has the value 0.

如果我只是：

$this->form_validation->set_rules('url', 'url', 'trim|xss_clean|callback_url_check');

并调用 url_check（$ str）

问题是如何传递两个值到 url_check（$ str，$ id）？

The question is how do I pass two values to the url_check($str, $id)?

推荐答案

您可以直接使用$ this-> input-> post：

You can use $this->input->post directly:

function check_url() {
   $url = $this->input->post('url');
   $id = $this->input->post('id');

   // do some database things you need to do e.g.
   if ($url_check = $this->user_model->check_url($url, $id) {
       return TRUE;
   }
   $this->form_validation->set_message('Url check is invalid');
   return FALSE;
}

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