当涉及对象字面量时,JavaScript是否提起if语句? [英] Does JavaScript hoist if statements when object literals are involved?

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本文介绍了当涉及对象字面量时,JavaScript是否提起if语句?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

  var foo = {}; document.body.innerHTML = console.log = location.hash ='Hi'+'< br> '+ foo.bar +'< br> '+ foo.baz; setTimeout(function(){foo.baz = foo [bar] = []; foo.bar.push(new Date); foo.baz.push(new Date); document.body.innerHTML = console.log = location.hash ='Hi'+'< br>'+ foo.bar +'< br>'+ foo.baz},5000);  

node.bar

解决方案

等于 false (node.foo&&& node.bar)将求值为 false 是否附加属性。不要检查这些属性是否 true ,您应该检查它们是否未定义:

  if(typeof node.foo!=='undefined'&&&typeof node.bar!=='undefined')
{
...
}
else
{
...
}


var foo = {}; document.body.innerHTML = console.log = location.hash = 'Hi ' + '<br>  ' + foo.bar + '<br>  ' + foo.baz; setTimeout(function(){foo.baz = foo["bar"] = []; foo.bar.push(new Date); foo.baz.push(new Date); document.body.innerHTML = console.log = location.hash = 'Hi ' + '<br>  ' + foo.bar + '<br>  ' + foo.baz}, 5000);

解决方案

Since you set node.bar equal to false, (node.foo && node.bar) will evaluate to false whether the properties are attached or not. Rather than checking if those properties are true, you should check whether they are undefined:

if (typeof node.foo !== 'undefined' && typeof node.bar !== 'undefined') 
{ 
  ...
} 
else 
{
  ...
}

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