如何在Android手机上使用phonegap显示相机 [英] how to display camera on Android phone by using phonegap
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问题描述
我想在Android手机上使用phonegap捕获图像。我尝试在Phonegap页上发布的代码，但相机不显示。非常感谢。非常感谢。非常感谢。
这是我手机上的显示
<！DOCTYPE html>
< html>
< head>
< title>捕获照片< / title>
< script type =text / javascriptcharset =utf-8src =cordova-1.6.0.js>< / script&
< script type =text / javascriptcharset =utf-8>
var pictureSource; // picture source
var destinationType; //设置返回值的格式
//等待Cordova连接设备
//
document.addEventListener（deviceready，onDeviceReady，false）;
// Cordova已准备好使用了！
//
function onDeviceReady（）{
pictureSource = navigator.camera.PictureSourceType;
destinationType = navigator.camera.DestinationType;
}
//成功检索照片时调用
//
函数onPhotoDataSuccess（imageData）{
//取消注释以查看base64编码图像数据
// console.log（imageData）;
//获取图像处理
//
var smallImage = document.getElementById（'smallImage'）;
//取消隐藏图片元素
//
smallImage.style.display ='block';
//显示捕获的照片
//内联CSS规则用于调整图像大小
//
smallImage.src =data：image / jpeg ; base64，+ imageData;
}
//成功检索照片时调用
//
函数onPhotoURISuccess（imageURI）{
//取消注释以查看图像文件URI
// console.log（imageURI）;
//获取图像句柄
//
var largeImage = document.getElementById（'largeImage'）;
//取消隐藏图片元素
//
largeImage.style.display ='block';
//显示捕获的照片
//内联CSS规则用于调整图像大小
//
largeImage.src = imageURI;
}
//按钮将调用此函数
//
function capturePhoto（）{
//使用设备摄像头拍摄图片并检索图片作为base64编码的字符串
navigator.camera.getPicture（onPhotoDataSuccess，onFail，{quality：50，
destinationType.DATA_URL}）;
}
//按钮将调用此函数
//
function capturePhotoEdit（）{
//使用设备摄像头拍摄图片，允许编辑，并检索图像为base64编码的字符串
navigator.camera.getPicture（onPhotoDataSuccess，onFail，{quality：20，allowEdit：true，
destinationType.DATA_URL}）;
}
//按钮将调用此函数
//
function getPhoto（source）{
//从指定源检索映像文件位置
navigator.camera.getPicture（onPhotoURISuccess，onFail，{quality：50，
destinationType：destinationType.FILE_URI，
sourceType：source}）;
}
//如果发生错误调用。
//
function onFail（message）{
alert（'Failed because：'+ message）;
}
< / script>
< / head>
< body>
< button onclick =capturePhoto（）;>捕获照片< / button> < br>
< button onclick =capturePhotoEdit（）;>捕获可编辑照片< / button> < br>
< button onclick =getPhoto（pictureSource.PHOTOLIBRARY）;>来自照片库< / button>< br>
< button onclick =getPhoto（pictureSource.SAVEDPHOTOALBUM）;>来自相簿< / button>< br>
< img style =display：none; width：60px; height：60px; id =smallImagesrc =/>
< img style =display：none; id =largeImagesrc =/>
< / body>
< / html> code c> c>
和 capturePhotoEdit（）函数需要更新 destinationType
navigator.camera.getPicture（
onPhotoDataSuccess，
onFail，
{
quality：50，
destinationType.DATA_URL
}
）;
应该是这样，
navigator.camera.getPicture（
onPhotoDataSuccess，
onFail，
{
quality：50，
destinationType：destinationType.DATA_URL
}
）;
I want to capture an image by using phonegap on Android phone. I try the code posted on Phonegap page but the camera does not appear. Any help is appreciated.Thank you very much.
It is the display on my phone
<!DOCTYPE html>
<html>
<head>
<title>Capture Photo</title>
<script type="text/javascript" charset="utf-8" src="cordova-1.6.0.js"></script>
<script type="text/javascript" charset="utf-8">
var pictureSource; // picture source
var destinationType; // sets the format of returned value
// Wait for Cordova to connect with the device
//
document.addEventListener("deviceready",onDeviceReady,false);
// Cordova is ready to be used!
//
function onDeviceReady() {
pictureSource=navigator.camera.PictureSourceType;
destinationType=navigator.camera.DestinationType;
}
// Called when a photo is successfully retrieved
//
function onPhotoDataSuccess(imageData) {
// Uncomment to view the base64 encoded image data
// console.log(imageData);
// Get image handle
//
var smallImage = document.getElementById('smallImage');
// Unhide image elements
//
smallImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
smallImage.src = "data:image/jpeg;base64," + imageData;
}
// Called when a photo is successfully retrieved
//
function onPhotoURISuccess(imageURI) {
// Uncomment to view the image file URI
// console.log(imageURI);
// Get image handle
//
var largeImage = document.getElementById('largeImage');
// Unhide image elements
//
largeImage.style.display = 'block';
// Show the captured photo
// The inline CSS rules are used to resize the image
//
largeImage.src = imageURI;
}
// A button will call this function
//
function capturePhoto() {
// Take picture using device camera and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
destinationType.DATA_URL });
}
// A button will call this function
//
function capturePhotoEdit() {
// Take picture using device camera, allow edit, and retrieve image as base64-encoded string
navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
destinationType.DATA_URL });
}
// A button will call this function
//
function getPhoto(source) {
// Retrieve image file location from specified source
navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
destinationType: destinationType.FILE_URI,
sourceType: source });
}
// Called if something bad happens.
//
function onFail(message) {
alert('Failed because: ' + message);
}
</script>
</head>
<body>
<button onclick="capturePhoto();">Capture Photo</button> <br>
<button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
<button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
<button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
<img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
<img style="display:none;" id="largeImage" src="" />
</body>
</html>
解决方案 Both your capturePhoto() and capturePhotoEdit() functions need to have the destinationType updated.
navigator.camera.getPicture(
onPhotoDataSuccess,
onFail,
{
quality: 50,
destinationType.DATA_URL
}
);
should be like this,
navigator.camera.getPicture(
onPhotoDataSuccess,
onFail,
{
quality: 50,
destinationType: destinationType.DATA_URL
}
);
这篇关于如何在Android手机上使用phonegap显示相机的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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