如何将列表值转换为int [英] how to convert a list value into int

问题描述

我有一个pyodbc行的值（9，）
我试图读取一个简单的整数变量的值，我发现，这么难这样做。 （我是新的python所以我可能错过了一些哑）

i have a pyodbc row with value (9, ) I am trying to read the value into a simple integer variable, and i find that its so hard to do so. (i am new to python so i probably miss something dumb)

做一个简单的 int（a_row [0]） get -

doing a simple int(a_row[0]) get -

TypeError: int() argument must be a string or a number, not 'pyodbc.Row'

我试图先将该行转换为列表，并且它的结果相同

i try to cast the row into a list first, and its the same result

我不得不强制它成一个整数值工作

i had to force it into a integer value to work

row_id=(2, )

temp_num=0

temp_num = [number for number in row_id[0]]

temp_num=int(temp_num[0])

我只是发现它真的很奇怪，我必须做一些这么愚蠢的事，所以它必须是我的错，

i just find it really bizarre that i have to do something so silly, so it must be my fault, can anyone enlighten me, where i got it wrong?

推荐答案

您的解决方案并没有将它强制为整数;它在 row_id [0] 中创建一个元素数组（ Row 一。所以你最初可以只做 a_row [0] [0] 。

Your solution isn't forcing it into an integer; it is creating an array of the elements (the Rows) in row_id[0], and then extracting the first one. So you could have just done a_row[0][0] initially.

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