jQuery的，JSON和Apache问题 [英] jQuery, JSON and Apache problem

问题描述

我有一个jQuery的JSON请求，加载一些JSON从另一台服务器（前foo.com）：

I have an jQuery JSON request, that loads some JSON from another server (ex. foo.com):

$.getJSON("http://foo.com/json.php",function(data) { alert(data); });

不过，我收到的数据为空。这不是跨域的问题，我尝试以下操作：

But I receive data as null. This is not cross-domain issue, I tried following:

$.getJSON("http://twitter.com/users/usejquery.json?callback=?",
    function(data) { alert(data); });

和收到不错的JSON对象。所以，我觉得有问题的后端，阿帕奇2.2.14。以下是HTTP头，从服务器发送的：

and received nice JSON object. So, I think there is problem with backend, Apache 2.2.14. Here are HTTP headers, sent from server:

Date: Sun, 07 Mar 2010 16:08:38 GMT
Server: Apache/2.2.14 (CentOS)
X-Powered-By: PHP/5.3.1
Content-Length: 2
Keep-Alive: timeout=15, max=99
Connection: Keep-Alive
Content-Type: application/json; charset=UTF-8

标头是在每种情况下相同的：普通的HTTP请求或AJAX。不过，我收到内容为空与AJAX和JSON正常使用浏览器请求。我使用萤火做检查，PHP5形成JSON。

The headers are the same in each case: regular HTTP-request or AJAX. But I receive empty content with AJAX, and normal JSON with browser request. I'm using Firebug for tests, PHP5 for forming JSON.

有人有什么想法？ 谢谢！

Somebody have any ideas? Thank you!

推荐答案

我是pretty的肯定，为了做到跨域调用，例如这一点，你必须有一个回调，这是我们所需要做的JSONP。

I'm pretty sure that in order to do cross domain calls like this you have to have a callback, it's what's needed to do JSONP.

这里是JSONP的 http://www.insideria.com/2009/03/what-in-the-heck-is-jsonp-and.html

有关JSONP工作，你必须有一个回调的服务器来包装的JSON字符串，例如：

For jsonp to work you have to have a callback for the server to wrap the json string in. for example:

$.getJSON("http://foo.com/json.php?callback=?", function(data){});

下面一个回调函数的jQuery产生并传递到请求，所以这将是这样的：

here a callback function is generated by jquery and passed into the request, so it would be something like:

http://foo.com/json.php?callback=generatedFunction

那么所返回的服务器应该是：

then what's returned by the server should be:

generatedFunction("{key:value, key2:value2}");

，其中在该函数的参数是实际JSON字符串

where the parameter in that function is the actual json string.

在PHP返回这一点，会是这样的：

in the php to return this it would be something like:

$callback = $_GET['callback'];
print($callback."(".json_encode($theobject).");");

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