将整数值存储在C中的字符数组中 [英] Store an integer value in a character array in C

问题描述

这是一个非常小的问题，但我不知道为什么我没有得到正确的输出。这是我想要做的：

It is a very trivial question but I don't know why I am not getting the correct output. Here is what I am trying to do:

char sendBuffer[1000];
int count=0:
while(count<10)
{
    sendBuffer[0]=count;
    sendBuffer[1]='a';
    sendBuffer[2]='b';
    sendBuffer[3]='c';
    sendBuffer[4]='\0';
    printf(%s,sendBuffer);
    count=count+1;
}

在输出中，除第一个索引外，所有缓冲区都正确打印。我想要1,2,3等等打印在缓冲区的开始，但它不工作。请帮助

In the output, all buffer is printed correctly except the first index. I want 1,2,3 and so on to be printed at the start of the buffer but it does not work. Please Help

推荐答案

您需要将该数字转换为字符。一个便宜的方法是：

You need to convert that number into a character. A cheap way to do it is:

sendBuffer[0] = '0' + count;

无论如何显示大于9的整数

is there anyway to display integers greater than 9

如果你需要，你会想转移到更复杂的方案。例如，如果要将整数42转换为字符串42，您可以说：

If you need that you'll want to shift to more elaborate schemes. For example, if you want to convert an integer 42 into the string "42" you can say:

#define ENOUGH ((CHAR_BIT * sizeof(int) - 1) / 3 + 2)

char str[ENOUGH];
snprint(str, sizeof str, "%d", 42);

贷款 ENOUGH 转到 caf 。

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