从文本文件中读取的第一个字符： [英] First character of the reading from the text file : 

问题描述

如果我写这个代码，我得到这个输出 - >第一：
然后其他行

If I write this code, I get this as output --> This first:  and then the other lines

try {
    BufferedReader br = new BufferedReader(new FileReader(
            "myFile.txt"));

    String line;
    while (line = br.readLine() != null) {
        System.out.println(line);
    }
    br.close();

} catch (FileNotFoundException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}

如何避免？

推荐答案

你在第一行得到字符因为这个序列是 UTF-8字节顺序标记（BOM）。如果文本文件以BOM开头，则可能是由记事本等Windows程序生成的。

You are getting the characters  on the first line because this sequence is the UTF-8 byte order mark (BOM). If a text file begins with a BOM, it's likely it was generated by a Windows program like Notepad.

为了解决您的问题，我们选择将文件显式地读为UTF -8，而不是任何默认系统字符编码（US-ASCII等）：

To solve your problem, we choose to read the file explicitly as UTF-8, instead of whatever default system character encoding (US-ASCII, etc.):

BufferedReader in = new BufferedReader(
    new InputStreamReader(
        new FileInputStream("myFile.txt"),
        "UTF-8"));

然后在UTF-8中，字节序列解码为一个字符，即U + FEFF。此字符是可选的 - 合法的UTF-8文件可以或不可以开头。因此，只有当它是U + FEFF时，才跳过第一个字符：

Then in UTF-8, the byte sequence  decodes to one character, which is U+FEFF. This character is optional - a legal UTF-8 file may or may not begin with it. So we will skip the first character only if it's U+FEFF:

in.mark(1);
if (in.read() != 0xFEFF)
  in.reset();

现在，您可以继续使用其余代码。

And now you can continue with the rest of your code.

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