UTF-8拉丁-1转换问题，python django [英] UTF-8 latin-1 conversion issues, python django

问题描述

确定，所以我的问题是我有字符串'\222\222\223\225'，它作为latin-1存储在db中。我从django（通过打印它）是以下字符串，'ââ¢'，我假设是它的UTF转换。现在我需要将字符串传递到一个函数，
做这个操作：

ok so my issue is i have the string '\222\222\223\225' which is stored as latin-1 in the db. What I get from django (by printing it) is the following string, 'ââââ¢' which I assume is the UTF conversion of it. Now I need to pass the string into a function that does this operation:

strdecryptedPassword + chr(ord(c) - 3 - intCounter - 30)

我得到这个错误：

chr（）arg不在范围内（256）

chr() arg not in range(256)

将字符串编码为latin-1首先我得到这个错误：

If I try to encode the string as latin-1 first I get this error:

'latin-1'编解码器不能编码位置0的字符-3：序数不是
在范围（256）

'latin-1' codec can't encode characters in position 0-3: ordinal not in range(256)

我已经读了一堆字符编码的工作原理，

I have read a bunch on how character encoding works, and there is something I am missing because I just don't get it!

推荐答案

您的第一个错误'chr（）arg不在范围内（256）'可能意味着你有下溢的值，因为chr不能取负数。我不知道加密算法应该做什么时，inputcounter + 33比实际的字符表示，你将不得不检查在这种情况下做什么。

Your first error 'chr() arg not in range(256)' probably means you have underflowed the value, because chr cannot take negative numbers. I don't know what the encryption algorithm is supposed to do when the inputcounter + 33 is more than the actual character representation, you'll have to check what to do in that case.

关于第二个错误。您必须解码（）而不是编码（）一个常规字符串对象，以获得正确的数据表示。 encode（）采用unicode对象（以u'开头的对象），并生成要输出或写入文件的常规字符串。 decode（）接受一个字符串对象并生成一个具有相应代码点的unicode对象。这是通过unicode（）调用从字符串对象生成时完成的，您也可以调用a.decode（'latin-1'）。

About the second error. you must decode() and not encode() a regular string object to get a proper representation of your data. encode() takes a unicode object (those starting with u') and generates a regular string to be output or written to a file. decode() takes a string object and generate a unicode object with the corresponding code points. This is done with the unicode() call when generated from a string object, you could also call a.decode('latin-1') instead.

>>> a = '\222\222\223\225'
>>> u = unicode(a,'latin-1')
>>> u
u'\x92\x92\x93\x95'
>>> print u.encode('utf-8')
ÂÂÂÂ
>>> print u.encode('utf-16')
ÿþ
>>> print u.encode('latin-1')

>>> for c in u:
...   print chr(ord(c) - 3 - 0 -30)
...
q
q
r
t
>>> for c in u:
...   print chr(ord(c) - 3 -200 -30)
...
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
ValueError: chr() arg not in range(256)

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