在Python中从字符串获取x个最低有效位 [英] Get the x Least Significant Bits from a String in Python

问题描述

如何从Python中的字符串（str）中获取x个LSB？
在具体的我有一个256位字符串组成32个字符，每个占用1个字节，从我必须得到一个char字符串与50个最低有效位。

mystr 保存我的字符串 $>

  [-7]）&（3））] 
 result2 = chrlist [-6：] 
 return.join（result1 + result2）
  

此函数接受 mystr 的-7rd字符的2个LSB（这些是50 LSB）
然后取出 mystr 的最后6个字符（这些是50 LSB的48个LSB）

如果我错误，请让我知道。

How can I get the x LSBs from a string (str) in Python? In the specific I have a 256 bits string consisting in 32 chars each occupying 1 byte, from wich i have to get a "char" string with the 50 Least Significant Bits.

解决方案

I think that a possible answer could be in this function: mystr holds my string

def get_lsbs_str(mystr):
    chrlist = list(mystr)
    result1 = [chr(ord(chrlist[-7])&(3))]
    result2 = chrlist[-6:]
    return "".join(result1 + result2)

this function take 2 LSBs of the -7rd char of mystr (these are the 2 MSBs of the 50 LSBs) then take the last 6 characters of mystr (these are the 48 LSB of the 50 LSB)

Please make me know if I am in error.

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