如何检查PHP中是否选中复选框？ [英] How do I check if checkbox is checked in PHP?
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问题描述
我想检查一个复选框是否已在PHP中检查为了注册。但它现在不工作。这是我目前使用的代码，以检查是否已经检查。
if（！isset（$ _ POST [ 'tos']））
$ this-> errors [] ='请接受我们的服务条款。
这是HTML代码。
< div class =checkbox>
< label>
< input type =checkboxname =tosvalue =0>我同意< a href =＃>服务条款< / a>和< a href =＃>隐私权政策< / a>
< / label>
< / div>
完整表单代码：
< form role =formmethod =POSTaction =<？php echo $ _SERVER ['PHP_SELF'];？>>
< div class =form-group>
< div class =row>
< div class =col-sm-6>
< label for =firstname> Firstname< / label>
< input type =textclass =form-controlid =firstnamename =firstnameplaceholder =Firstname>
< / div>
< div class =col-sm-6>
< label for =surname>姓氏< / label>
< input type =textclass =form-controlid =surnamename =surnameplaceholder =Surname>
< / div>
< / div>
< / div>
< div class =form-group>
< label for =username>用户名< / label>
< input type =textclass =form-controlid =rusername =ruserplaceholder =Username>
< / div>
< div class =form-group>
< label for =email2>电子邮件地址< / label>
< input type =emailclass =form-controlid =remailname =remailplaceholder =输入电子邮件>
< / div>
< div class =form-group>
< div class =row>
< div class =col-sm-6>
< label for =password2>密码< / label>
< input type =passwordclass =form-controlid =rpassname =rpassplaceholder =密码>
< / div>
< div class =col-sm-6>
< label for =password2>重复密码< / label>
< input type =passwordclass =form-controlid =rpass2name =rpass2placeholder =密码>
< / div>
< / div>
< / div>
< div class =checkbox>
< / label>
< / div>
< input type =hiddenname =securvalue =<？php echo $ ip;？>/>
< input type =hiddenname =tokenvalue =<？php echo $ token;？>/>
< button type =submitname =registerclass =btn btn-block btn-color btn-xxl>创建帐户< / button>
< / form>
此代码有什么问题？任何帮助将不胜感激。
解决方案
if（！isset（$ _ POST ['tos ']））
$ this-> errors [] ='请接受我们的服务条款';`
这么做是说如果$ _POST中没有tos，就会抛出一个错误。
真的你应该检查这个客户端
您也可以...
$ b $ b
< input type =checkboxname =tosvalue =accepted
和PHP：
if（isset（$ _ POST ['tos']）&& $ _POST ['tos'] ==='accepted'）echo'All good';
else array_push（$ errors，'err code here'）; //添加到$ error数组
更新 b
$ b
我不知道你是不是使用jQuery，但是只是为了更方便用户的方法：
var tos = $（'＃tos'）;
var notice = $（'。notice'）;
tos.on（'click'，function（）{
if（tos.is（'：checked'））{
notice.text（'Thank you。'）;
}
else {
notice.text（'请接受我们的ToS继续。'）;
}
}）
查看此处的工作示例。如果没有选中，你甚至可以一起停止表单。 BTW，如果我记得正确复选框输入只有在选中时才发送POST数据。
I am trying to check if a checkbox have been checked in PHP in order to register. But it's not working right now. This is the code I am using so far, to check if it have been checked.
if(!isset($_POST['tos']))
$this->errors[] = 'Please accept our Terms of Service.';
And this is the HTML code.
<div class="checkbox">
<label>
<input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
</label>
</div>
Full form code:
<form role="form" method="POST" action="<?php echo $_SERVER['PHP_SELF'];?>">
<div class="form-group">
<div class="row">
<div class="col-sm-6">
<label for="firstname">Firstname</label>
<input type="text" class="form-control" id="firstname" name="firstname" placeholder="Firstname">
</div>
<div class="col-sm-6">
<label for="surname">Surname</label>
<input type="text" class="form-control" id="surname" name="surname" placeholder="Surname">
</div>
</div>
</div>
<div class="form-group">
<label for="username">Username</label>
<input type="text" class="form-control" id="ruser" name="ruser" placeholder="Username">
</div>
<div class="form-group">
<label for="email2">Email address</label>
<input type="email" class="form-control" id="remail" name="remail" placeholder="Enter email">
</div>
<div class="form-group">
<div class="row">
<div class="col-sm-6">
<label for="password2">Password</label>
<input type="password" class="form-control" id="rpass" name="rpass" placeholder="Password">
</div>
<div class="col-sm-6">
<label for="password2">Repeat password</label>
<input type="password" class="form-control" id="rpass2" name="rpass2" placeholder="Password">
</div>
</div>
</div>
<div class="checkbox">
<label>
<input type="checkbox" name="tos" value="0"> I agree to the <a href="#">Terms of Service</a> and <a href="#">Privacy Policy</a>
</label>
</div>
<input type="hidden" name="secur" value="<?php echo $ip;?>"/>
<input type="hidden" name="token" value="<?php echo $token;?>"/>
<button type="submit" name="register" class="btn btn-block btn-color btn-xxl">Create an account</button>
</form>
What's wrong with this code? Any help would be appreciated.
解决方案
if(!isset($_POST['tos']))
$this->errors[] = 'Please accept our Terms of Service.';`
What this is doing is saying if there is no 'tos' in $_POST, throw an error.
Really you should probably check this client side with javascript, before the form is sent to the server.
You could also...
<input type="checkbox" name="tos" value="accepted" checked>
And PHP:
if(isset($_POST['tos']) && $_POST['tos']==='accepted') echo 'All good';
else array_push($errors,'err code here'); //to add to $error array
Update
I'm not sure if you're using jQuery or not, but just for a more user friendly approach:
var tos = $('#tos');
var notice = $('.notice');
tos.on('click',function(){
if(tos.is(':checked')){
notice.text('Thank you.');
}
else{
notice.text('Please accept our ToS to continue.');
}
})
See a working example here. You could even halt the form all together if it's unchecked. BTW, if I remember correctly checkbox inputs only send POST data if checked.
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