PHP类:全局变量作为类中的属性 [英] PHP class: Global variable as property in class

查看:656
本文介绍了PHP类:全局变量作为类中的属性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的类外有一个全局变量= $ MyNumber;

I have a global variable outside my class = $MyNumber;



如何在 myClass

对于类中的每个方法,这都是我所做的:


How do I declare this as a property in myClass?
For every method in my class, this is what I do:

class myClass() {

    private function foo() {
         $privateNumber = $GLOBALS['MyNumber'];
    }

}

>
我想要这个



I want this

class myClass() {

    //What goes here?
    var $classNumber = ???//the global $MyNumber;

    private function foo() {
         $privateNumber = $this->classNumber;
    }

}

>

编辑:我想根据全局$ MyNumber创建一个变量,但在使用它之前修改

方法

I want to create a variable based on the global $MyNumber but
modified before using it in the methods

类似:var $ classNumber = global $ MyNumber + 100;

something like: var $classNumber = global $MyNumber + 100;

推荐答案

您可能不希望这样做,因为它将是一个噩梦去调试,但似乎是可能的。关键是在构造函数中通过引用分配的部分。

You probably don't really want to be doing this, as it's going to be a nightmare to debug, but it seems to be possible. The key is the part where you assign by reference in the constructor.

$GLOBALS = array(
    'MyNumber' => 1
);

class Foo {
    protected $glob;

    public function __construct() {
        global $GLOBALS;
        $this->glob =& $GLOBALS;
    }

    public function getGlob() {
        return $this->glob['MyNumber'];
    }
}

$f = new Foo;

echo $f->getGlob() . "\n";
$GLOBALS['MyNumber'] = 2;
echo $f->getGlob() . "\n";

输出将为

1
2

,而不是价值。

正如我所说,这将是一个噩梦来调试,所以你真的不应该这样做。阅读关于封装的维基百科文章;基本上,你的对象应该理想地管理自己的数据和数据被修改的方法;甚至公共财产一般,IMHO,一个坏主意。

As I said, it will be a nightmare to debug, so you really shouldn't do this. Have a read through the wikipedia article on encapsulation; basically, your object should ideally manage its own data and the methods in which that data is modified; even public properties are generally, IMHO, a bad idea.

这篇关于PHP类:全局变量作为类中的属性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆