Javascript获取类的实例名称 [英] Javascript get name of instance of class

问题描述

function myClass(a,b,c) {
     this.alertMyName=function(){alert(instancename)}

{...}


}

and then

foo = myClass(a,b,c);
boo = myClass(a,b,c);

foo.alertMyName(); //it should alert 'foo'
boo.alertMyName(); //it should alert 'boo'

在实践中，我需要它为类创建很多html对象前缀他们的ID来区分它们与由该类的另一个实例创建的同一对象。

In practice I'll need it for class that is creating a lot of html objects to prefix their ID's to differentiate them from same object created by another instance of this class.

推荐答案

answer，javascript中的变量具有一个值，它是一个原始或对对象的引用。如果值是引用，那么它引用的东西不知道变量的名称是什么。

Further to David's answer, variables in javascript have a value that is either a primitive or a reference to an object. Where the value is a reference, then the thing it references has no idea what the "name" of the variable is.

请考虑：

var foo = new MyThing();
var bar = foo;

现在应该 foo.alertMyName（） return？甚至：

So now what should foo.alertMyName() return? Or even:

(new MyThing()).alertMyName();

如果你想要实例有一个名字，然后给他们一个属性， 。

If you want instances to have a name, then give them a property and set its value to whatever suits.

这篇关于Javascript获取类的实例名称的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！