简单的C ++ getter / setters [英] Simple C++ getter/setters
本文介绍了简单的C ++ getter / setters的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
最近我写的getter和setter为(注意:真正的类在getter / setter中做更多的事情):
Lately I'm writing my getter and setters as (note: real classes do more things in getter/setter):
struct A {
const int& value() const { return value_; } // getter
int& value() { return value_; } // getter/setter
private:
int value_;
};
它允许我执行以下操作:
which allows me to do the following:
auto a = A{2}; // non-const object a
// create copies by "default" (value always returns a ref!):
int b = a.value(); // b = 2, is a copy of value :)
auto c = a.value(); // c = 2, is a copy of value :)
// create references explicitly:
auto& d = a.value(); // d is a ref to a.value_ :)
decltype(a.value()) e = a.value(); // e is a ref to a.value_ :)
a.value() = 3; // sets a.value_ = 3 :)
cout << b << " " << c << " " << d << " " << e << endl; // 2 2 3 3
const auto ca = A{1};
const auto& f = ca.value(); // f is a const ref to ca.value_ :)
auto& g = ca.value(); // no compiler error! :(
// g = 4; // compiler error :)
decltype(ca.value()) h = ca.value(); // h is a const ref to ca.value_ :)
//ca.value() = 2; // compiler error! :)
cout << f << " " << g << " " << h << endl; // 1 1 1
这种方法不允许我:
- 验证setter的输入(这是一个很大的BUT),
- 在const成员函数中返回值我想让编译器捕捉到const对象的赋值:
ca.value()= 2
)。更新:请参阅下面的cluracan答案。
- validate the input for the setter (which is a big BUT),
- return by value in the const member function (because I want the compiler to catch assignment to const objects:
ca.value() = 2
). Update: see cluracan answer below.
但是,我仍然使用这个很多,因为
However, I'm still using this a lot because
- 大多数时候我不需要它,
- 这使我能够从我们的接口中分离出我的类的实现细节,这就是我想要的。
示例:
struct A {
const int& value(const std::size_t i) const { return values_[i]; }
int& value(const std::size_t i) { return values_[i]; }
private:
std::vector<int> values_;
// Storing the values in a vector/list/etc is an implementation detail.
// - I can validate the index, but not the value :(
// - I can change the type of values, without affecting clients :)
};
现在回答问题:
- 这种方法还有其他缺点吗?
- 为什么人们喜欢:
- getter / setters方法具有不同的名称?
- 将值作为参数传递?
只是用于验证输入或有其他主要原因吗?
推荐答案
- 通常使用访问器/ mutator是一个设计的气味,你的类public接口是不完整的。通常来说,你想要一个有用的公共接口,提供有意义的功能,而不是简单的get / set(这只比一个或两个步骤比我们在结构和函数的C)。每次你想写一个mutator,并且很多时候你想写一个访问器,只是退后一步,问你自己
我真的*需要这个吗?
- 只有习惯用语的人可能不准备期望这样的功能,所以它会增加维护者的时间来梳理你的代码。
- 同名方法几乎与公共成员相同:在这种情况下只使用公共成员。当方法做两个不同的事情,命名他们两个不同的东西。
- 非const引用返回的mutator将允许各种各样的别名问题,给成员,依靠它以后存在。通过使用单独的设置器功能,您可以防止用户对您的私人数据进行别名。
- Generally using accessors/mutators at all is a design smell that your class public interface is incomplete. Typically speaking you want a useful public interface that provides meaningful functionality rather than simply get/set (which is just one or two steps better than we were in C with structs and functions). Every time you want to write a mutator, and many times you want to write an accessor first just take a step back and ask yourself
"do I *really* need this?"
. - Just idiom-wise people may not be prepared to expect such a function so it will increase a maintainer's time to grok your code.
- The same-named methods are almost the same as the public member: just use a public member in that case. When the methods do two different things, name them two different things.
- The "mutator" returning by non-const reference would allow for a wide variety of aliasing problems where someone stashes off an alias to the member, relying on it to exist later. By using a separate setter function you prevent people from aliasing to your private data.
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