将变量列表单独传递给clojure函数 [英] Passing list of variables individually to clojure function

问题描述

我一直在玩clojure，并决定做一个更高阶的函数，结合mapcat和列表来模拟这种行为：

I have been playing around with clojure, and decided to make a higher order function that combines mapcat and list to emulate this behavior:

Clojure> (mapcat list '(1 2 3 4) '(5 6 7 8))
(1 5 2 6 3 7 4 8)

我的第一个尝试是定义mapcatList如下：

my first attempt was defining mapcatList as follows:

Clojure> (defn mapcatList[& more](mapcat list more))
#'sandbox99/mapcatList
Clojure> (mapcatList '(1 2 3 4) '(5 6 7 8))
((1 2 3 4) (5 6 7 8))

很明显，这个函数并不是我想要的，我认为这是因为两个列表被放入一个列表中，并作为一个参数传递，而不是两个。
我可以用以下方法补救这种情况：

Obviously the function does not behave how I would like it, and I think this is because the two lists are being put into one list and passed as a single argument, not two. I was able to remedy the situation with the following,

Clojure> (defn mapcatList[x y & more](mapcat list x y))
#'sandbox99/mapcatList
Clojure> (mapcatList '(1 2 3 4) '(5 6 7 8))
(1 5 2 6 3 7 4 8)

这个解决方案适用于两个列表，但我希望函数使用可变数量的参数。

This solution works well with two lists, but I would like the function to work with a variable number of arguments.

我的问题：如何传递一个可变数量的参数到一个函数，然后解构它们，使它们作为单独的参数一起传递到'mapcat list' p>

My question: How can I pass a variable number of argument to a function, then destructure them so they are passed as individual arguments together to 'mapcat list'?

推荐答案

您正在寻找 apply 。

但是你知道有一个函数 interleave 您的 mapcatList 尝试做什么？

But are you aware that there's a function interleave that does exactly what your mapcatList tries to do?

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