如何做出累积序列？ [英] How to make a cumulative sequence?

问题描述

说我有一个延迟序列，如下所示：

Say I have a lazy sequence like the following:

(def s (iterate inc 1))
(take 10 s)
=> (1 2 3 4 5 6 7 8 9 10)

现在， s 的累计总和如下：

Now, I want to generate a sequence of cumulative sum of s like the following:

=> (1 3 6 10 15 ...)

我该如何做？
我尝试使用 atom 并累加和（mutating）这是生成累积序列的唯一方法，还是有更好的方法这？

How can I do this? What I tried is to use atom and accumulate the sum to it(mutating) Is this the only way to generate cumulative sequence or is there a better way to do this?

注意：上面的累积和只是一个例子。源序列可以是其他序列。所以我不能使用公式： s（n）= n（n + 1）/ 2

NOTE: the above cumulative sum is only an example. The source sequence can be other sequence. So I can't use formula: s(n) = n(n+1)/2

推荐答案

(take 10 (reductions + s))
=> (1 3 6 10 15 21 28 36 45 55)

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